我正在尝试设置一个脚本，以抓取youtube视频以php下载它们，这是我当前的脚本。
<html>
<?php
if(!empty($_POST['name'])) {
$location = htmlspecialchars($_POST['name']);
try {
$handle = fopen($location, "r");
if($handle) {
$contents = '';
while (!feof($handle)) {
$contents .= fread($handle, 8192);
}
fclose($handle);
$result1 = preg_match("/&t=([\w]*)&/",$contents,$tickets);
$result2 = preg_match("/v=(\w*)/",$location,$video_id);
if($result1) {
echo "<a href = \"http://www.youtube.com/get_video?video_id=";
echo $video_id[1];
echo "&t=";
echo $tickets[1];
echo "\">Download link.</a>";
echo "<br>";
echo "Click and Save";
}
else echo "Damn! Click Back and try again..Sorry :(";
}
else echo "\nYou liked that? Ha?";
}
catch(Exception $e) {echo "I made an error. So what? COME AT ME BRO!";}
}
else echo "Empty input! YOU'RE SO STUPID!";
?>
<br><br>
<a href="face.html">Back</a>
</hmtl>
我还有一个简单的HTML文件，该文件提供了将YouTube URL粘贴到字段中并在其中运行上述脚本的地方。但是我得到回声
Damn! Click Back and try again..Sorry :("我不知道为什么会收到此错误，该代码对我来说有什么建议？
最佳答案
不久前，我偶然发现了这一点:
<?php
$id = 'O99Sqpxd0hE';
$format = 'video/mp4';
parse_str(file_get_contents("http://www.youtube.com/get_video_info?video_id=" . $id), $info);
$streams = $info['url_encoded_fmt_stream_map'];
$streams = explode(',', $streams);
foreach($streams as $stream) {
parse_str($stream, $data);
if(stripos($data['type'], $format) !== false) {
$video = fopen($data['url'] . '&signature=' . $data['sig'], 'r');
$file = fopen($_GET['id'] . '.mp4', 'w');
stream_copy_to_stream($video, $file);
fclose($video);
fclose($file);
echo '<a href="./'.$_GET['id'].'.mp4">Download</a>';
die();
}
}
?>
关于php - 用PHP抓取YouTube上的视频，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/21026981/