hadoop - 如何将没有任何分隔符的字符串转换为逗号分隔的字符串？

Question

我有一个文件 details.txt，其中存储的数据就是这种格式

        "571955NandhithaF1975-12-222011-12-06Mumbai"    

列是前六位唯一标识， 姓名、(男/女)性别、出生日期、入职日期和地点 我必须使用逗号分隔符将其分成六列!! 请帮我解决这个问题

Answer 1

将每一行传递给包含以下逻辑的正则表达式函数:

    String expression = "571955NandhithaF1975-12-222011-12-06Mumbai";

    Pattern pattern = Pattern
            .compile("([0-9]{6})([a-zA-Z]+)([M|F])([0-9]{4}-[0-9]{2}-[0-9]{2})([0-9]{4}-[0-9]{2}-[0-9]{2})([a-zA-Z0-9]+)");
    Matcher matcher = pattern.matcher(expression);
    if (matcher.find()) {
        //System.out.println(matcher.group());
        System.out.println(matcher.group(1));
        System.out.println(matcher.group(2));
        System.out.println(matcher.group(3));
        System.out.println(matcher.group(4));
        System.out.println(matcher.group(5));
        System.out.println(matcher.group(6));
    }

输出:

571955
Nandhitha
F
1975-12-22
2011-12-06
Mumbai