php - YouTube API : Displaying thumbnails of each video. ..？

Question

您好，有人可以帮助我以正确的方式从我拉入的 channel 中获取每个视频的 default.jpg 图像吗？

<?php
$url = 'http://gdata.youtube.com/feeds/api/users/utahblaze/uploads?orderby=updated&max-results=8';
$xml = simplexml_load_file($url);
foreach ($xml->entry as $entry) :

    $kids = $entry->children('http://search.yahoo.com/mrss/');
    $attributes = $kids->group->content[0]->attributes();
    $flv = $attributes['url'];
    $attributes = $kids->group->player->attributes();
    $link = $attributes['url']; 
?>

<a href="<?=$link?>">test</a?
<?php endforeach; ?>

Answer 1

这里是如何使用 Zend Framework 的 GData Youtube 类获取视频的图像 url 的示例。

<?php 
$yt = new Zend_Gdata_YouTube();
$query = $yt->newVideoQuery();
$query->videoQuery = 'cat';
$query->startIndex = 10;
$query->maxResults = 20;
$query->orderBy = 'viewCount';

$videoFeed = $yt->getVideoFeed($query);

foreach ($videoFeed as $videoEntry) : ?>
    <div class="video"> 
        <span>Title: <?php echo $videoEntry->getVideoTitle();?><span><br />
        <span>Description:<?php echo $videoEntry->getVideoDescription();?> </span> <br/>
        <?php $videoThumbnails = $videoEntry->getVideoThumbnails(); ?>
        <img alt="video-thumbnail" src="<?php echo $videoThumbnails[0]['url'];?>" />
    </div>
<?php endforeach; ?>

正如您所看到的，getVideoThumbnails() 方法为您提供了该视频的缩略图数组及其内部的 url。希望这会有所帮助。