flutter - 在屏幕水龙头上显示应用栏或平面按钮

Question

我有一个视频播放器，并且有一个自定义按钮可以返回。我想在屏幕上显示该按钮，然后在1或2秒钟后隐藏。可以是透明的应用栏，可在屏幕上显示并点按并隐藏，并且该应用栏包含自定义按钮

Answer 1

输出:



完整代码:

void main() => runApp(MaterialApp(home: YourPage()));

class YourPage extends StatefulWidget {
  @override
  _YourPageState createState() => _YourPageState();
}

class _YourPageState extends State<YourPage> {
  bool _showControls = false; // set it to false initially

  _showAndHideControls() {
    // show controls the moment user tapped on screen
    setState(() => _showControls = true);

    // after 2 seconds, hide the controls
    Timer(Duration(seconds: 2), () {
      setState(() => _showControls = false);
    });
  }

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      appBar: _showControls ? AppBar(title: Text("AppBar")) : null,
      body: Center(
        child: RaisedButton(
          child: Text("Click me"),
          onPressed: _showAndHideControls,
        ),
      ),
    );
  }
}