比方说,在文件 中裁剪.csv ,我有一个简单的数据集,格式如下:
id,cropType,cropName
1,food,rice
2,cash,sugarcane
3,horticulture,orange
我有一个名为 的模型类粮食裁剪 :
class foodCrops {
int id;
String cropType;
String cropName;
foodCrops(this.id, this.cropType, this.cropName);
}
如何将这些数据从 csv 文件转换为 类食品裁剪一览 ?
List<foodCrops>
最佳答案
在这里,我只是解析这些行以制作 FoodCrop
的实例类(class)。您可以根据需要解析数据。
void main() {
var foodCrops = makeFoodCropList();
for (var foodCrop in foodCrops) {
print(foodCrop);
}
}
List<FoodCrop> makeFoodCropList() {
var lines = [
'id,cropType,cropName',
'1,food,rice',
'2,cash,sugarcane',
'3,horticulture,orange',
];
lines.removeAt(0); //remove column heading
/*
* you can use any parser for csv file,
*
* a csv package is available
* or simple file reading will also get the job done main logic is coded here
* */
var list = <FoodCrop>[];
for (var line in lines) list.add(FoodCrop.fromList(line.split(',')));
return list;
}
class FoodCrop {
int id;
String cropType;
String cropName;
FoodCrop(this.id, this.cropType, this.cropName);
FoodCrop.fromList(List<String> items) : this(int.parse(items[0]), items[1], items[2]);
@override
String toString() {
return 'FoodCrop{id: $id, cropType: $cropType, cropName: $cropName}';
}
}
关于csv - Dart:如何将 CSV 数据映射到模型列表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60079848/