dart - Dart:以String作为参数的函数作为回调中的参数

Question

我现在正在学习Flutter，尝试编写一个简单的计算器。我正在使用此代码构建行:

Row(    // creates row
mainAxisAlignment: MainAxisAlignment.spaceEvenly, //row is spaced evenly
children: <Widget>[
   _button("4", _number("4")), //calls _button widget passing String 4 and function _number, which passes string 4 also
   _button("5", _number("5")), //button with value 5
   _button("6", _number("6")), //button with value 6
   _button("-", _min("null")) //button for subtraction
  ],
),

我的_button小部件如下所示:

Widget _button(String number, Function() f(String number)){ //parameters: the button value as String and the function with the value as String
  return MaterialButton(
    height: buttonHeight,
    minWidth: buttonHeight,
    child: Text(number,
        style: TextStyle(fontWeight: FontWeight.bold, fontSize: 48.0)),
    textColor: Colors.black,
    color: Colors.grey[100],
    onPressed: f,  //function is called
  );
}

现在，我想将字符串号传递给函数f，因此在调用函数_number时，它将获取字符串号并将其粘贴到显示器上:

void _number(String number){
  setState(() {
   display=display + number ;
  });
}

它不起作用，我试图解决它，但是没有成功。有人有主意吗？

谢谢!

Answer 1

您必须更改此:

Widget _button(String number, Function() f(String number)){ //parameters: the button value as String and the function with the value as String
  return MaterialButton(
    height: buttonHeight,
    minWidth: buttonHeight,
    child: Text(number,
        style: TextStyle(fontWeight: FontWeight.bold, fontSize: 48.0)),
    textColor: Colors.black,
    color: Colors.grey[100],
    onPressed: f,  //function is called
  );

为了这:

Widget _button(String number, Function(String number) f){ //parameters: the button value as String and the function with the value as String
  return MaterialButton(
    height: buttonHeight,
    minWidth: buttonHeight,
    child: Text(number,
        style: TextStyle(fontWeight: FontWeight.bold, fontSize: 48.0)),
    textColor: Colors.black,
    color: Colors.grey[100],
    onPressed: () {
       f(number); // function is called
    },  
  );

主要变化是参数位于Function(String param1, String param2) nameFunction内，在您的情况下为Function(String number) f