我正在尝试调用 List
中的 remoteConfig
字符串
class HomeModel {
final RemoteConfig remoteConfig; //HomeModel() is called in Home() and fetches the param from there
HomeModel({this.remoteConfig});
List taskList = [
{
'title': 'Hello',
'url': remoteConfig.getString(''),
},
];
}
但是,它向我显示错误 -
The instance member 'remoteConfig' can't be accessed in an initializer
最佳答案
将taskList
的初始化移至initState()
。
List taskList;
@override
void initState() {
taskList = [
{
'title': 'Hello',
'url': remoteConfig.getString(''),
},
];
super.initState();
}
关于firebase - Flutter - 无法在初始化程序中访问实例成员 'remoteConfig',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/63655222/