我需要编写函数echo,它将文件名和浮点值time_delay表示为秒数,然后echo应该处理声音,原始声音被自身的副本覆盖而向前移动按time_delay及时。
这是我到目前为止所拥有的:
def add_scale_2(L, M, L_scale, M_scale):
""" add_scale_2 has as intput list L and list M and rertuns a new list LC,
with a linear sum of the two lists times their scale respectively. LC will use the length of the
shortest list
"""
if len(L) >= len (M):
N = len(M)
else:
N = len(L)
LC = [L[i]*L_scale + M[i]*M_scale for i in range(N)]
return LC
和:
def echo(filename, time_delay):
print "Playing filename1 ..."
play(filename)
print "Reading in the sound data..."
samps1, sr = readwav(filename)
samps2 = [0]*float(samps1*time_delay) + samps1
print "Computing new sound..."
newsamps = add_scale_2(samps1, samps2, 0.5, 0.5)
newsr = sr # no change to the sr
writewav( newsamps, newsr, "out.wav" )
print "Playing new sound..."
play( 'out.wav' )
有人可以帮我,因为我不明白!
samps2 = [0]*int(samps1*time_delay) + samps1
TypeError: can't multiply sequence by non-int of type 'float'
最佳答案
您的电话:
[0]*float(samps1*time_delay) + samps1
尝试将序列
[0]
与float
相乘。导致错误TypeError: can't multiply sequence by non-int of type 'float'
您可以改成int:
[0]*int(len(samps1)*time_delay) + samps1
关于python - 声音回声函数Python,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32887906/