elasticsearch - 如何按ID中的文档对Elasticsearch进行排序？

Question

我正在使用Bonsai的免费层，并试图编写一个脚本来管理我的Elastic索引中的文档数。为了最大程度地保存文档，我想开始删除其中包含许多嵌套文档的文档。
例:

{   
 "title": "Spiderman saves child from well",   
 "body":  "Move over, Lassie! New York has a new hero. But is he also a menace?",   
 "authors": [
   { 
      "name":  "Jonah Jameson",       
      "title": "Sr. Editor",     
   },     
   {       
      "name":  "Peter Parker",       
      "title": "Photos",     
   }   
  ],   
 "comments": [     
   {       
      "username": "captain_usa",       
      "comment":  "I understood that reference!",     
   },     
   {       
      "username": "man_of_iron",       
      "comment":  "Congrats on being slightly more useful than a ladder.",     
   }   
  ],   
 "photos": [ 
   {       
      "url":      "https://assets.dailybugle.com/12345",       
      "caption":  "Spiderman delivering Timmy back to his mother",     
   }   
  ] 
 }
    

Elastic中有什么可以告诉我该文档由于广泛的嵌套而实际上是6个文档吗？理想情况下，我将能够通过此“文档计数”对 flex 记录进行排序。
谢谢!

Answer 1

如果您的authors，comments和photos被琐碎地嵌套(对象数组)或专用elasticsearch nested 数据类型的，则可以执行以下操作:

GET bonsai/_search
{
  "_source": [""], 
  "sort": [
    {
      "_script": {
        "type": "number",
        "script": {
          
          "source": """
            def count = 1; // top level doc count is 1
            for (def entry : params._source.values()) {
              if (entry instanceof ArrayList) {
                count += entry.size()
              }
            }
            return count;
          """
        }
      }
    }
  ]
}

我真的不知道上面的文档的大小是6怎么做-所以我想这是因为您也计算了顶级文档。随意在脚本中从0开始计数。