嗨,我正在努力将保存在手机上的音频文件上传到服务器,在下面的代码中,我将DoOutput设置为true,但仍为false。当我尝试新的DataOutputStream时出现错误,为什么?
FATAL EXCEPTION: main
Process:com.example.dialectdata, PID: 2296
java.lang.RuntimeException: Failure delivering result ResultInfo{who=null,request=2, result=-1, data=Intent { dat=content://com.android.providers.media.documents/document/audio:11464 flg=0x1 }} to activity{com.example.dialectdata/com.example.dialectdata.MainActivity}: android.os.NetworkOnMainThreadException
运行调试后,似乎以下代码附带了错误。
这里selectedPath是电话上的文件路径,而urlString是php文件的地址。的
private void doFileUpload(){
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "rn";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "https://unintermitted-modul.000webhostapp.com/upload.php";
try
{
FileInputStream fileInputStream = new FileInputStream(new File(selectedPath) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name="uploadedfile";filename="" + selectedPath + """ + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
这是我在服务器端的PHP代码。
<?php
$target_path= "uploads/";
$target_path= $target_path. basename($_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'],$target_path))
{
echo"The file ". basename($_FILES['uploadedfile']['name']).
" has been uploaded";
}else{
echo"There was an error uploading the file, please try again!";
echo"filename: " . basename($_FILES['uploadedfile']['name']);
echo"target_path: " .$target_path;
}
?>
提前非常感谢您。
doFileUpload()在这里执行:
public void openGalleryAudio(){
Intent intent = new Intent();
intent.setType("audio/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent,"Select Audio "), SELECT_AUDIO);
}
public void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == RESULT_OK) {
if (requestCode == SELECT_AUDIO)
{
System.out.println("SELECT_AUDIO");
Uri selectedImageUri = data.getData();
selectedPath = getPath(selectedImageUri);
System.out.println("SELECT_AUDIO Path : " + selectedPath);
doFileUpload();
}
}
}
单击按钮时执行openGalleryAudio()
最佳答案
尝试在AsyncTask中做到这一点:
new AsyncTask<Void, Void, Void>()
{
@Override
protected Void doInBackground(Void... params)
{
doFileUpload();
return null;
}
}.execute();
关于php - 使用Android Studio将音频文件上传到服务器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45708616/