powershell - 从文件计算时间

Question

基于my previous question(感谢@MartinBrandl)，我也想获取时间值来计算时间。

示例数据:

07:30 - 07:45PMTS09526052 | Sev9 | Location| | Due: 12/23/2016
NON PC HARDWARE - TROUBLESHOOT SW
Complete this Job

马丁·布兰德尔(Martin Brandl)提出了这个方案，以获得我需要的其他数据:

Select-String $WLDir -pattern '(PMT[S|T]\d{8})' -Context 0,2 | ForEach-Object {
[PSCustomObject]@{
    Time = $_.Matches.Groups[1].Value
    Topic = $_.Context.PostContext[0]
    Status = $_.Context.PostContext[1]
}
} | ConvertTo-Csv -NoTypeInformation

我想从07:30 - 07:45部分的前面抓取PMT位。我打算用这个来获取时间:

$StartTime = [However I get the `7:30` here]
$EndTime = [However I get the `7:45` here]
$ElapsedTime = (NEW-TIMESPAN –Start $StartTime –End $EndTime).TotalHours

然后将第四个字段添加到CSV:

Elapsed = $ElapsedTime

但是我不确定如何抓紧两次并将它们隔离为变量。有人可以协助吗？

Answer 1

在您的第一个问题中，时间跨度不在Csv中
正则表达式没有引用它。现在是7:30是$ matches.groups [1] .value等

$WLDir = ".\File.txt" 
$Pattern='(\d{2}:\d{2}) - (\d{2}:\d{2})(PMT[S|T]\d{8})'
Select-String $WLDir -pattern $Pattern -Context 0,2 |
    ForEach-Object {
        $StartTime=[datetime]::ParseExact($_.Matches.Groups[1].Value,"HH:mm",$null)
        $EndTime=[datetime]::ParseExact($_.Matches.Groups[2].Value,"HH:mm",$null)
        $ElapsedTime = (NEW-TIMESPAN –Start $StartTime –End $EndTime).TotalHours
        [PSCustomObject]@{
            Time = $_.Matches.Groups[3].Value
            Topic = $_.Context.PostContext[0]
            Status = $_.Context.PostContext[1]
            ElapsedHrs = $ElapsedTime
        }
} | ConvertTo-Csv -NoTypeInformation

提供此输出(我在PMTT中添加了第二个测试项)

"Time","Topic","Status","ElapsedHrs"
"PMTS09526052","NON PC HARDWARE - TROUBLESHOOT SW","Complete this Job","0,25"
"PMTT10952605","NON PC HARDWARE - TROUBLESHOOT SW","Complete this Job","0,25"

时间列仍然不包含时间
(我的语言环境有一个十进制逗号)