python - 用空格传递Python JSON参数

Question

我试图在命令提示符下将JSON作为参数传递给python脚本。如果JSON中的元素的值中没有空格，则它起作用，但是如果有空格，则它不起作用。
这是脚本

import json, sys, traceback
    if(len(sys.argv)>1):
    print(sys.argv[1])
    jsonInput = json.loads(sys.argv[1]);
    print(jsonInput['name'])
    print(jsonInput['kingdom'])
    print(jsonInput['slogan'])

在JSON之下作为power Shell中的参数传递。我的值中有空格，例如乔恩·雪诺

python C:\Users\user1\Desktop\myTest.py '{\"name\":\"Jon Snow\",\"kingdom\":\"Winterfell\",\"slogan\":\"King in the North\"}'

输出:

python : Traceback (most recent call last):
At line:1 char:1
+ python C:\Users\kiran.patil\Desktop\myTest.py '{\"name\":\"Jon Snow\" ...
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    + CategoryInfo          : NotSpecified: (Traceback (most recent call last)::String) [], RemoteException
    + FullyQualifiedErrorId : NativeCommandError
 
  File "C:\Users\User\Desktop\myTest.py", line 5, in <module>
    jsonInput = json.loads(sys.argv[1]);
  File "C:\Program Files\Python38\lib\json\__init__.py", line 357, in loads
    return _default_decoder.decode(s)
  File "C:\Program Files\Python38\lib\json\decoder.py", line 337, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "C:\Program Files\Python38\lib\json\decoder.py", line 353, in raw_decode
    obj, end = self.scan_once(s, idx)
json.decoder.JSONDecodeError: Unterminated string starting at: line 1 column 9 (char 8)

请任何建议对其进行修复。

Answer 1

如果您使用\"，则表示括起来的引号也是双引号。在Windows上，封闭的单引号不起作用，因此2个选项是

# Linux + Windows
python script.py "{\"name\":\"Jon Snow\",\"kingdom\":\"Winterfell\",\"slogan\":\"King in theNorth\"}"

# Linux only
python script.py '{"name":"Jon Snow","kingdom":"Winterfell","slogan":"King in theNorth"}'

Powershell shell

python script.py '{""name"":""Jon Snow"",""kingdom"":""Winterfell"",""slogan"":""King in theNorth""}'