arrays - 使用Hive在数组中创建结构

Question

我正在 hive 中为Twitter json文件创建表。这是示例文件。我面临的问题是我无法使用结构创建数组，因为在以下数据中，单个数组中有4个相同的结构。谁能告诉我如何为以下数据创建数组。我尝试给每个结构指定不同的名称，该表已成功创建，但无法从table.Kindly Help中提取数据。
谢谢

> "variants": [
         {
           "bitrate": 2176000,
           "content_type": "video\/mp4",
           "url": "https:\/\/video.twimg.com\/ext_tw_video\/560070131976392705\/pu\/vid\/1280x720\/c4E56sl91ZB7cpYi.mp4"
         },
         {
           "bitrate": 320000,
           "content_type": "video\/mp4",
           "url": "https:\/\/video.twimg.com\/ext_tw_video\/560070131976392705\/pu\/vid\/320x180\/nXXsvs7vOhcMivwl.mp4"
         },
         {
           "bitrate": 832000,
           "content_type": "video\/webm",
           "url": "https:\/\/video.twimg.com\/ext_tw_video\/560070131976392705\/pu\/vid\/640x360\/vmLr5JlVs2kBLrXS.webm"
         },
         {
           "bitrate": 832000,
           "content_type": "video\/mp4",
           "url": "https:\/\/video.twimg.com\/ext_tw_video\/560070131976392705\/pu\/vid\/640x360\/vmLr5JlVs2kBLrXS.mp4"
         },
         {
           "content_type": "application\/x-mpegURL",
           "url": "https:\/\/video.twimg.com\/ext_tw_video\/560070131976392705\/pu\/pl\/r1kgzh5PmLgium3-.m3u8"
         }
       ]

Answer 1

试试这个，

CREATE TABLE complex_json (
  variants:array<struct<bitrate:int,content_type:string, url:string>>>
)
ROW FORMAT SERDE 'org.openx.data.jsonserde.JsonSerDe';

从https://github.com/rcongiu/Hive-JSON-Serde获得Serde