sql - 如何使用周六作为周结束日期在 hive 中计算周结束日期？

Question

考虑到周六在周六结束，我有一种情况要计算周结束日期(给定日期)。我读了一些答案，但是找不到解决方案，所以我在这里发布我的方法。希望它能帮助像我这样的人。

select 
TransactionDateTime,
from_unixtime(unix_timestamp(TransactionTime),'u') as wkday,
date_add (TransactionDateTime,
case when from_unixtime(unix_timestamp(TransactionTime),'u')=7 then 6 
when from_unixtime(unix_timestamp(TransactionTime),'u')=1 then 5
when from_unixtime(unix_timestamp(TransactionTime),'u')=2 then 4
when from_unixtime(unix_timestamp(TransactionTime),'u')=3 then 3
when from_unixtime(unix_timestamp(TransactionTime),'u')=4 then 2
when from_unixtime(unix_timestamp(TransactionTime),'u')=5 then 1
when from_unixtime(unix_timestamp(TransactionTime),'u')=6 then 0
end) as UsageWkEndDt
from TransTable;

Answer 1

select 
TransactionDateTime,
from_unixtime(unix_timestamp(TransactionTime),'u') as wkday,
date_add (TransactionDateTime,
case when from_unixtime(unix_timestamp(TransactionTime),'u')=7 then 6 
when from_unixtime(unix_timestamp(TransactionTime),'u')=1 then 5
when from_unixtime(unix_timestamp(TransactionTime),'u')=2 then 4
when from_unixtime(unix_timestamp(TransactionTime),'u')=3 then 3
when from_unixtime(unix_timestamp(TransactionTime),'u')=4 then 2
when from_unixtime(unix_timestamp(TransactionTime),'u')=5 then 1
when from_unixtime(unix_timestamp(TransactionTime),'u')=6 then 0
end) as UsageWkEndDt
from TransTable;