我有这张图片,我需要找到的位置(仅)在左上方的框及其宽度和高度。如何在openCV中使用Python做到这一点? enter image description here
最佳答案
这是在Python / OpenCV / Numpy中执行此操作的一种方法。
输入:
import cv2
import numpy as np
# read input
img = cv2.imread("table_cells.png")
hh, ww = img.shape[:2]
# convert to gray
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
# threshold to binary
thresh = cv2.threshold(gray, 0, 255, cv2.THRESH_BINARY)[1]
# get sum of black values in rows and columns
row_sums = np.sum(thresh==0, axis=1)
column_sums = np.sum(thresh==0, axis=0)
# threshold sums to counts above 80% of hh and ww
row_sums[np.where(row_sums<0.8*ww)] = 0
column_sums[np.where(column_sums<0.8*hh)] = 0
# find coordinates that have non-zero values
row_coords = np.argwhere(row_sums>0)
column_coords = np.argwhere(column_sums>0)
num_rows = len(row_coords)
num_cols = len(column_coords)
# filter row_coords to avoid duplicates within 10 pixels
row_coords_filt = [row_coords[0]]
for i in range(num_rows-1):
if (row_coords[i] > row_coords[i-1]+10):
row_coords_filt.append(row_coords[i])
column_coords_filt = [column_coords[0]]
for i in range(num_cols-1):
if (column_coords[i] > column_coords[i-1]+10):
column_coords_filt.append(column_coords[i])
# print row_coords_filt
print('grid row coordinates:')
for c in row_coords_filt:
print (c)
print('')
# print column_coords_filt
print('grid column coordinates:')
for c in column_coords_filt:
print (c)
# get left, right, top, bottom of upper left rectangle
left = int(column_coords_filt[0])
right = int(column_coords_filt[1])
top = int(row_coords_filt[0])
bottom = int(row_coords_filt[1])
# crop rectangle
rectangle = img[top:bottom, left:right]
# save output
cv2.imwrite('table_cells_crop.png', rectangle)
cv2.imshow('thresh', thresh)
cv2.imshow('rectangle', rectangle)
cv2.waitKey(0)
cv2.destroyAllWindows()
裁剪矩形:
找到的座标:
grid row coordinates:
[30]
[315]
[599]
[884]
grid column coordinates:
[41]
[790]
[1540]
[2289]
关于python - 我如何使用Python openCV在表格的这张图片中找到左上角框的位置(x,y,宽度,高度)?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61842616/