我正在使用pangu的三个图像来使用emgucv和C#测试图像的倾斜度。
位于顶部的第一张图像检测到180度正常工作。
中间检测到的90度第二张图像应检测为180度。
检测到的第三个图像180度应检测为90度。
我想在这里分享的一个观察结果是,当我使用画笔从潘卡的上下两边裁剪掉不需要的图像部分时,使用下面提到的代码可以给我预期的结果。
现在,我想了解如何使用编程来删除不需要的部分。
我玩过轮廓和roi,但我不知道该如何拟合。我无法理解emgucv本身是选择轮廓还是必须做一些事情。
请提出任何合适的代码示例。
请检查以下代码以进行 Angular 检测,并请帮助我。提前致谢。
imgInput = new Image<Bgr, byte>(impath);
Image<Gray, Byte> img2 = imgInput.Convert<Gray, Byte>();
Bitmap imgs;
Image<Gray, byte> imgout = imgInput.Convert<Gray, byte>().Not().ThresholdBinary(new Gray(50), new Gray(125));
VectorOfVectorOfPoint contours = new VectorOfVectorOfPoint();
Emgu.CV.Mat hier = new Emgu.CV.Mat();
var blurredImage = imgInput.SmoothGaussian(5, 5, 0 , 0);
CvInvoke.AdaptiveThreshold(imgout, imgout, 255, Emgu.CV.CvEnum.AdaptiveThresholdType.GaussianC, Emgu.CV.CvEnum.ThresholdType.Binary, 5, 45);
CvInvoke.FindContours(imgout, contours, hier, Emgu.CV.CvEnum.RetrType.External, Emgu.CV.CvEnum.ChainApproxMethod.ChainApproxSimple);
if (contours.Size >= 1)
{
for (int i = 0; i <= contours.Size; i++)
{
Rectangle rect = CvInvoke.BoundingRectangle(contours[i]);
RotatedRect box = CvInvoke.MinAreaRect(contours[i]);
PointF[] Vertices = box.GetVertices();
PointF point = box.Center;
PointF edge1 = new PointF(Vertices[1].X - Vertices[0].X, Vertices[1].Y - Vertices[0].Y);
PointF edge2 = new PointF(Vertices[2].X - Vertices[1].X, Vertices[2].Y - Vertices[1].Y);
double r = edge1.X + edge1.Y;
double edge1Magnitude = Math.Sqrt(Math.Pow(edge1.X, 2) + Math.Pow(edge1.Y, 2));
double edge2Magnitude = Math.Sqrt(Math.Pow(edge2.X, 2) + Math.Pow(edge2.Y, 2));
PointF primaryEdge = edge1Magnitude > edge2Magnitude ? edge1 : edge2;
double primaryMagnitude = edge1Magnitude > edge2Magnitude ? edge1Magnitude : edge2Magnitude;
PointF reference = new PointF(1, 0);
double refMagnitude = 1;
double thetaRads = Math.Acos(((primaryEdge.X * reference.X) + (primaryEdge.Y * reference.Y)) / (primaryMagnitude * refMagnitude));
double thetaDeg = thetaRads * 180 / Math.PI;
imgInput = imgInput.Rotate(thetaDeg, new Bgr());
imgout = imgout.Rotate(box.Angle, new Gray());
Bitmap bmp = imgout.Bitmap;
break;
}
}
最佳答案
问题
让我们从解决方案之前的问题开始:
您的密码
当您提交代码时,寻求帮助,至少需要付出一些努力来“清理”它。帮助人们帮助您!这里有太多的代码行什么都不做。您声明从未使用过的变量。添加一些注释,使人们知道您认为代码应该执行的操作。
Bitmap imgs;
var blurredImage = imgInput.SmoothGaussian(5, 5, 0, 0);
Rectangle rect = CvInvoke.BoundingRectangle(contours[i]);
PointF point = box.Center;
double r = edge1.X + edge1.Y;
// Etc
自适应阈值以下代码行产生以下图像:
CvInvoke.AdaptiveThreshold(imgout, imgout, 255, Emgu.CV.CvEnum.AdaptiveThresholdType.GaussianC, Emgu.CV.CvEnum.ThresholdType.Binary, 5, 45);
图片1 图片2
图片3
显然,这不是您要的目标,因为主要轮廓(卡片边缘)已完全丢失。作为提示,您始终可以使用以下代码在运行时显示图像,以帮助您进行调试。
CvInvoke.NamedWindow("Output");
CvInvoke.Imshow("Output", imgout);
CvInvoke.WaitKey();
tu由于您的示例图像中的卡片主要是与背景(在HSV意义上)相似的值。在这种情况下,我认为简单的灰度阈值化不是正确的方法。我的目的是:
算法
WarpAffine
应用的转换矩阵。编码
您可能希望尝试使用Canny Detection and Dilation参数。
// Working Images
Image<Bgr, byte> imgInput = new Image<Bgr, byte>("Test1.jpg");
Image<Gray, byte> imgEdges = new Image<Gray, byte>(imgInput.Size);
Image<Gray, byte> imgDilatedEdges = new Image<Gray, byte>(imgInput.Size);
Image<Bgr, byte> imgOutput;
// 1. Edge Detection
CvInvoke.Canny(imgInput, imgEdges, 25, 80);
// 2. Dilation
CvInvoke.Dilate(
imgEdges,
imgDilatedEdges,
CvInvoke.GetStructuringElement(
ElementShape.Rectangle,
new Size(3, 3),
new Point(-1, -1)),
new Point(-1, -1),
5,
BorderType.Default,
new MCvScalar(0));
// 3. Contours Detection
VectorOfVectorOfPoint inputContours = new VectorOfVectorOfPoint();
Mat hierarchy = new Mat();
CvInvoke.FindContours(
imgDilatedEdges,
inputContours,
hierarchy,
RetrType.External,
ChainApproxMethod.ChainApproxSimple);
VectorOfPoint primaryContour = (from contour in inputContours.ToList()
orderby contour.GetArea() descending
select contour).FirstOrDefault();
// 4. Corner Point Extraction
RotatedRect bounding = CvInvoke.MinAreaRect(primaryContour);
PointF topLeft = (from point in bounding.GetVertices()
orderby Math.Sqrt(Math.Pow(point.X, 2) + Math.Pow(point.Y, 2))
select point).FirstOrDefault();
PointF topRight = (from point in bounding.GetVertices()
orderby Math.Sqrt(Math.Pow(imgInput.Width - point.X, 2) + Math.Pow(point.Y, 2))
select point).FirstOrDefault();
PointF botLeft = (from point in bounding.GetVertices()
orderby Math.Sqrt(Math.Pow(point.X, 2) + Math.Pow(imgInput.Height - point.Y, 2))
select point).FirstOrDefault();
PointF botRight = (from point in bounding.GetVertices()
orderby Math.Sqrt(Math.Pow(imgInput.Width - point.X, 2) + Math.Pow(imgInput.Height - point.Y, 2))
select point).FirstOrDefault();
double boundingWidth = Math.Sqrt(Math.Pow(topRight.X - topLeft.X, 2) + Math.Pow(topRight.Y - topLeft.Y, 2));
double boundingHeight = Math.Sqrt(Math.Pow(botLeft.X - topLeft.X, 2) + Math.Pow(botLeft.Y - topLeft.Y, 2));
bool isLandscape = boundingWidth > boundingHeight;
// 5. Define warp crieria as triangles
PointF[] srcTriangle = new PointF[3];
PointF[] dstTriangle = new PointF[3];
Rectangle ROI;
if (isLandscape)
{
srcTriangle[0] = botLeft;
srcTriangle[1] = topLeft;
srcTriangle[2] = topRight;
dstTriangle[0] = new PointF(0, (float)boundingHeight);
dstTriangle[1] = new PointF(0, 0);
dstTriangle[2] = new PointF((float)boundingWidth, 0);
ROI = new Rectangle(0, 0, (int)boundingWidth, (int)boundingHeight);
}
else
{
srcTriangle[0] = topLeft;
srcTriangle[1] = topRight;
srcTriangle[2] = botRight;
dstTriangle[0] = new PointF(0, (float)boundingWidth);
dstTriangle[1] = new PointF(0, 0);
dstTriangle[2] = new PointF((float)boundingHeight, 0);
ROI = new Rectangle(0, 0, (int)boundingHeight, (int)boundingWidth);
}
Mat warpMat = new Mat(2, 3, DepthType.Cv32F, 1);
warpMat = CvInvoke.GetAffineTransform(srcTriangle, dstTriangle);
// 6. Apply the warp and crop
CvInvoke.WarpAffine(imgInput, imgInput, warpMat, imgInput.Size);
imgOutput = imgInput.Copy(ROI);
imgOutput.Save("Output1.bmp");
使用了两种扩展方法:static List<VectorOfPoint> ToList(this VectorOfVectorOfPoint vectorOfVectorOfPoint)
{
List<VectorOfPoint> result = new List<VectorOfPoint>();
for (int contour = 0; contour < vectorOfVectorOfPoint.Size; contour++)
{
result.Add(vectorOfVectorOfPoint[contour]);
}
return result;
}
static double GetArea(this VectorOfPoint contour)
{
RotatedRect bounding = CvInvoke.MinAreaRect(contour);
return bounding.Size.Width * bounding.Size.Height;
}
产出元示例
关于c# - emgucv:C#中的Pan Card不当偏斜检测,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62550517/