我正在通过 html 上传img，并在打开的简历中处理它并显示图像。我在arg parsers中有upload_file.py。所以我直接以python3 upload_file.py --listofargs的形式运行应用程序
template.html
<html>
<form action="{{ url_for('handle_data') }}" method="post">
<input type="file" id="imageInput" name="file" enctype="multipart/form-data">
<ul class="list-group list-group-flush">
<li class="list-group-item">
<button type="submit" class="btn btn-primary">Colorize</button>
</li>
</ul>
</form>
<img src = {{image}}>
</html>
upload_file.py
from flask import Flask, render_template, request
import cv2
from flask import jsonify
import argparse
import numpy as np
app = Flask(__name__)
@app.route('/', methods=['POST','GET'])
def index():
return render_template('template.html')
@app.route('/handle_data', methods=['POST','GET'])
def handle_data():
img = request.form['file']
image = np.array(img)
cv2.imshow("Original", image)
return render_template(template.html, image = image)
How it is working ?
python3 upload_file.py --listofargs命令直接将 flask 应用程序作为flask run运行。 Internal server error 如何解决错误，以便可以通过
img正确读取上载的html并通过 flask 显示回opencv img？
最佳答案
在Python3中，您可以这样做:
import numpy as np
import cv2
from io import BytesIO # not necessary?
def handle_data():
img = request.form['file']
image = cv2.imdecode(np.frombuffer(BytesIO(img).read(), np.uint8), cv2.IMREAD_UNCHANGED)
cv2.imshow("Original", image) # Why do you need this?
return render_template('template.html', image = image) # Don't forget the quotes?
那应该使您有足够的能力自行处理html渲染[我不是专家，但是如果有人可以提供帮助，我会将其合并到此答案中。]
让我知道这是否适合您
关于python - Flask:TypeError:参数 '%s'的预期Ptr <cv::UMat>，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/58640945/