grails - 如何在Config.groovy中使用环境变量

Question

在Config.groovy内部，我设置了一些环境变量:

def appName = grails.util.Metadata.current.getApplicationName()
def casUrl  = "https://login.cas.server/cas"
environments {
    development {
        grails.logging.jul.usebridge = true
        host.address = "12.34.56.78"
        host.port = "8080"
    }
    test {
        grails.logging.jul.usebridge = true
        host.address = "http://staging.server.somewhere.com/"
        host.port = ""
    }
    production {
        grails.logging.jul.usebridge = false
        host.address = "http://www.production.com"
        host.port = ""
    }
 }

我正在尝试在同一配置文件(Config.groovy)中使用这些值，如下所示:

grails.plugin.springsecurity.cas.loginUri = '/login'
grails.plugin.springsecurity.cas.serviceUrl = "${host.address}:${host.port}/${appName}/j_spring_cas_security_check"
grails.plugin.springsecurity.cas.serverUrlPrefix = '${casUrl}'
grails.plugin.springsecurity.cas.proxyCallbackUrl = "/secure/receptor"
grails.plugin.springsecurity.logout.afterLogoutUrl = "${casUrl}/logout?url=${host.address}:${host.port}/${appName}/"

但是，唯一要解决的是appName变量，其他所有内容都为null。这是可以做到的吗？看来它是在此帖子中用过的Grails: Spring Security CAS Working in 2.2.3，但我似乎无法解决它们。

如果我做类似的事情

def appName = grails.util.Metadata.current.getApplicationName()
def casUrl = "https://login.umt.edu/cas"
host.address = "MyAddress"
environments {
...

configSlurper解析CAS配置内的host.address，为什么我不能访问环境变量？

Answer 1

请参阅基本配置下的答案here。

However, you can't nest after using the dot notation. In other words, this won't work

// Won't work!
foo.bar {
    hello = "world"
    good = "bye"
}

因此，尝试使用这样的嵌套

foo {
   bar {
    hello = "world"
    good = "bye"
   }
}