有没有办法将嵌套的JSON值映射到字段而无需其他类?我有JSON回应
{
"title": "Warriors",
"artist": "Imagine Dragons",
"apple_music": {
"url": "https://music.apple.com/us/album/warriors/1440831203?app=music&at=1000l33QU&i=1440831624&mt=1",
"discNumber": 1,
"genreNames": [
"Alternative",
"Music"
],
}
}
但是从
apple_music
我只需要url
值。因此,我决定创建Kotlin数据类,并尝试了带有@Json
批注的选项data class Song(
val title: String,
val artist: String,
@Json(name = "apple_music.url")
val appleMusicUrl: String
)
但是,这不起作用。
它在运行时引发异常
Required value 'appleMusicUrl' (JSON name 'apple_music.url') missing at $
下面的代码正在工作
data class Song(
val title: String,
val artist: String,
@Json(name = "apple_music")
val appleMusic: AppleMusic
)
data class AppleMusic(val url: String)
我有几个嵌套的值,并且为它们创建额外的类非常麻烦。除了为
apple_music
节点创建嵌套类之外,还有什么更好的方法吗?
最佳答案
一种方法是使用alternate type adapters using @JsonQualifier。例如:
@Retention(RUNTIME)
@JsonQualifier
annotation class AppleMusicUrl
data class Song(
val title: String,
val artist: String,
@AppleMusicUrl
val appleMusicUrl: String
)
@FromJson
@AppleMusicUrl
fun fromJson(json: Map<String, Any?>): String {
return json.getValue("url") as String
}
关于android - Moshi将嵌套的JSON值映射到字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61825805/