我是RX Java的新手,我知道如何使用zip或平面 map ,但是我有以下问题,我感到无法选择:
我有一种方法,我试图重构:
updateDetails(emailAddress: String?, updateEmail: Boolean,
nickName: String?, updateNickName: Boolean,
avatarFile: File?, updateAvatar: Boolean)
现在,根据方法中的每个 bool(boolean) 值,我确定是否要更新电子邮件,昵称或头像。 Earleir是通过if条件和单独的API调用实现的。有没有一种方法可以使用提供的标志压缩或合并 call ?
最佳答案
您可以以阻塞的方式实现它:
fun updateDetails(emailAddress: String?, updateEmail: Boolean,
nickName: String?, updateNickName: Boolean,
avatarFile: File?, updateAvatar: Boolean) {
if (updateEmail) {
updateEmail(emailAddress).blockingGet()
}
if (updateNickName) {
updateNickName(nickName).blockingGet()
}
// ...
}
或者您可以像这样构建链并最终订阅它:
fun updateDetails(emailAddress: String?, updateEmail: Boolean,
nickName: String?, updateNickName: Boolean,
avatarFile: File?, updateAvatar: Boolean) {
var chain = Completable.complete()
if (updateEmail) {
chain = chain.andThen(updateEmail(emailAddress).ignoreElement())
}
if (updateNickName) {
chain = chain.andThen(updateNickName(nickName).ignoreElement())
}
// ...
chain
.subscribeOn(..)
.observeOn(..)
.subscribe()
}
或链接可完成项:
fun updateDetails(emailAddress: String?, updateEmail: Boolean,
nickName: String?, updateNickName: Boolean,
avatarFile: File?, updateAvatar: Boolean) {
Completable.defer {
if (updateEmail) {
updateEmail(emailAddress)
.ignoreElement()
} else {
Completable.complete()
}
}
.andThen(Completable.defer {
if (updateNickName) {
updateNickName(nickName)
.ignoreElement()
} else {
Completable.complete()
}
})
// ...
.subscribeOn(..)
.observeOn(..)
.subscribe()
}
关于kotlin - 基于 bool 值的Rx Java调用Api,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55703697/