kotlin - 如何将MutableList添加到其他MutableList-Kotlin？

Question

下午好，亲爱的StackOverflow社区，
我在Kotlin中使用MutableList遇到问题。更具体地说，我没有成功在MutableList 内添加MutableList。
例如，后面的例子

fun main() {

    var mutableListIndex: MutableList<Int> = mutableListOf<Int>()
    var mutableListTotal: MutableList<MutableList<Int>> = mutableListOf<MutableList<Int>>()

    for(i in 0..5) {
        mutableListIndex.add(i)
        println(mutableListIndex)

        mutableListTotal.add(mutableListIndex)
        println(mutableListTotal)

    }
}

我得到以下结果

[0]
[[0]]
[0, 1]
[[0, 1], [0, 1]]
[0, 1, 2]
[[0, 1, 2], [0, 1, 2], [0, 1, 2]]
[0, 1, 2, 3]
[[0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3]]
[0, 1, 2, 3, 4]
[[0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]
[0, 1, 2, 3, 4, 5]
[[0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5]]

一会儿，我期待结果

[0]
[[0]]
[0, 1]
[[0], [0, 1]]
[0, 1, 2]
[[0], [0, 1], [0, 1, 2]]
[0, 1, 2, 3]
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3]]
[0, 1, 2, 3, 4]
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]]
[0, 1, 2, 3, 4, 5]
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5]]

我没有成功理解我错了，因为从严格的算法 Angular 来看，我认为代码是好的。
有人可以帮我解释我的错误吗？
您忠诚的

Answer 1

遵循上面的Animesh Sahu先生的建议，我最终遵循以下解决方案:

fun main() {

    var mutableListIndex: MutableList<Int> = mutableListOf<Int>()
    var mutableListTotal: MutableList<MutableList<Int>> = mutableListOf<MutableList<Int>>()

    for(i in 0..5) {


        mutableListIndex.add(i)
        println(mutableListIndex)


        mutableListTotal.add(mutableListIndex.toMutableList())
        println(mutableListTotal)

    }
}

给出:

[0]
[[0]]
[0, 1]
[[0], [0, 1]]
[0, 1, 2]
[[0], [0, 1], [0, 1, 2]]
[0, 1, 2, 3]
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3]]
[0, 1, 2, 3, 4]
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4]]
[0, 1, 2, 3, 4, 5]
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5]]

非常感谢您的及时答复和帮助
您忠诚的