java - 如何从Android动态生成的表格中获得点击时的列号？

Question

我有一个在应用程序中以编程方式生成的表。我能够获取所选行的位置并将其分配给变量，但是我不确定如何对列执行等效操作，例如。我真正需要知道的是如何像在这里对行进行操作一样，获取列号:

fun createTable(rows: Int, cols: Int) {
        /* Here, 'i' represents the number of rows, which is determined by
        * the length of the location list active in the application. */
        for (i in 0 until locationList.size) {
            /* Instantiate the row that will be used to generate each table. */
            val row = TableRow(this)

            /* Set the basic layout parameters for the textView, which is being used to contain the table. */
            row.layoutParams = ViewGroup.LayoutParams(ViewGroup.LayoutParams.MATCH_PARENT, ViewGroup.LayoutParams.MATCH_PARENT)

            row.setOnClickListener {
                selectedRow = i.toString().toInt()

                if (locationList[selectedRow].entranceNoteArray.size == 0) {
                    showAlert("There are no transitions associated with this location. You may only add a note to an existent transition.")
                } else {
                    isEnterOrExit()
                }
            }

            row.gravity = Gravity.CENTER

            for (j in 0 until columns) {
                var rowIterator = 0
                val textView = TextView(this)

                textView.apply {
                    // Cosmetic/UI Related Code
                    textView.setPadding(10, 5, 10, 5)
                    layoutParams = TableRow.LayoutParams(350, TableRow.LayoutParams.WRAP_CONTENT)
                    textView.setTextColor(Color.DKGRAY)
                    textView.gravity = Gravity.CENTER
                    textView.textSize = 12F

                    /* The purpose of this decision structure is to fill the
                    * table's cells properly based upon which column cell 'j'
                    * represents. When j = 0 and i = 0, the first column of
                    * the first row has been selected - therefore, the first
                    * value (message) of the first location in the reversed
                    * locationList should be placed there. */
                    if (j == 0) {
                        text = locationList[i].message
                        textView.setTypeface(null, Typeface.BOLD)
                    } else if (j == 1) {
                        text = locationList[i].entered
                        textView.setTypeface(null, Typeface.NORMAL)
                    } else if (j == 2) {
                        text = locationList[i].exited
                    }
                }
                row.addView(textView)
                rowIterator++
            }
            tableLayout.addView(row)
        }
        logLayout.addView(tableLayout)
    }

有没有简单的方法可以做到这一点，或者我需要从 View 本身获取点击坐标才能以环形方式实现这一点？

Answer 1

如果您想知道在表中确切单击了哪个TextView，可以通过以下方式进行操作:

Foreach TextView您必须添加tag

textView.tag = "$i $j"

i是行，j是列。

现在您可以为每个TextView添加一个侦听器

textView.setOnClickListener {
    val tag = it.tag.toString()
    val row = tag.substring(0, tag.indexOf(' ')).toInt()
    val column = tag.substring(tag.indexOf(' ') + 1).toInt()
            
    //now You know which position was clicked
}