Java long number太大错误？

Question

为什么我得到一个 int number is too large where long 被分配给 min 和 max？

/*
long: The long data type is a 64-bit signed two's complement integer.
It has a minimum value of -9,223,372,036,854,775,808 and a maximum value of         9,223,372,036,854,775,807 (inclusive).
Use this data type when you need a range of values wider than those provided by int.
*/
package Literals;

public class Literal_Long {
     public static void main(String[] args) {
        long a = 1;
        long b = 2;
        long min = -9223372036854775808;
        long max = 9223372036854775807;//Inclusive

        System.out.println(a);
        System.out.println(b);
        System.out.println(a + b);
        System.out.println(min);
        System.out.println(max);
    }
}

Answer 1

java 中的所有字面量数字默认为 ints，范围为 -2147483648 到 2147483647。

您的文字超出此范围，因此要进行编译，您需要指出它们是 long 文字(即带有 L 的后缀):

long min = -9223372036854775808L;
long max = 9223372036854775807L;

注意java同时支持大写L和小写l，但我建议不要使用小写l，因为它看起来像一个 1:

long min = -9223372036854775808l; // confusing: looks like the last digit is a 1
long max = 9223372036854775807l; // confusing: looks like the last digit is a 1

Java Language Specification一样的

An integer literal is of type long if it is suffixed with an ASCII letter L or l (ell); otherwise it is of type int (§4.2.1).