我正在学习 Spring WebSocket。我已成功运行此 Spring WebSocket教程。现在我试图将它按原样合并到我现有的 Spring MVC 应用程序中。当我从 Chrome 浏览器运行它时,我在其开发控制台中看到以下错误。
Chrome 控制台
Opening Web Socket...
GET http://localhost:8080/MyAppName/api/gs-guide-websocket/info?t=1497735312528 500 (Internal Server Error) -- abstract-xhr.js:132
Whoops! Lost connection to http://localhost:8080/MyAppName/api/gs-guide-websocket -- stomp.min.js:8
服务器端错误
javax.servlet.ServletException: Could not resolve view with name '/MyAppName/api/gs-guide-websocket/info' in servlet with name 'MyAppName'
at org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1262)
at org.springframework.web.servlet.DispatcherServlet.processDispatchResult(DispatcherServlet.java:1037)
客户端
function connect() {
var socket = new SockJS('/MyAppName/api/gs-guide-websocket');
stompClient = Stomp.over(socket);
stompClient.connect({}, function (frame) {
setConnected(true);
console.log('Connected: ' + frame);
stompClient.subscribe('/topic/greetings', function (greeting) {
showGreeting(JSON.parse(greeting.body).content);
});
});
}
服务器端
@Configuration
@EnableWebSocketMessageBroker
public class WebSocketConfig extends AbstractWebSocketMessageBrokerConfigurer {
@Override
public void configureMessageBroker(MessageBrokerRegistry config) {
config.enableSimpleBroker("/topic");
config.setApplicationDestinationPrefixes("/app");
}
@Override
public void registerStompEndpoints(StompEndpointRegistry registry) {
registry.addEndpoint("/MyAppName/api/gs-guide-websocket").withSockJS();
}
}
我已经尝试解决这个问题几个小时了。我该如何解决?
泰
最佳答案
如果您的应用程序上下文是 MyAppName
那么你不需要在 addEndpoint
中指定它方法 - 此路径与您的应用程序上下文相关。
大概 registry.addEndpoint("/MyAppName/api/gs-guide-websocket")
使用路径 /MyAppName/MyAppName/api/gs-guide-websocket
注册端点
关于spring - SockJS 无法创建/连接到 Spring WebSocket,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44609914/