c++ - 在Linux上的C++中执行Shell命令xdotool

Question

#include <unistd.h>
#include <cstdio>
#include <iostream>
#include <string.h>

using namespace std;

int main(void)
{

//  Trying to execute:
//      xdotool mousemove 1500 1500

//    char command[] = "/usr/bin/xdotool\0";
    char command[] = "xdotool\0";
    char argument[] = "mousemove\0";
    int src_x = 1500;
    int src_y = 1500;

    char x[5];
    memset(x, 0x00, 5);
    sprintf(x, "%d", src_x);
    char y[5];
    memset(y, 0x00, 5);
    sprintf(y, "%d", src_y);

    cout << "command is " << command << "\n";
    cout << "argument is " << argument << "\n";
    cout << "x is " << x << "\n";
    cout << "y is " << y << "\n\n";

    char *args[] = {argument, x, y, nullptr};
    return execvp(command, args);
/*    char *args[] = {x, y, nullptr};
    char *com[] = {argument, nullptr};
    return execvpe(command, com, args);
    */
}

此代码有什么问题？
该命令运行，但似乎将每个参数解释为另一个执行。
不确定，但是我相信它正在运行:

xdotool mousemove
xdotool 1500
xdotool 1500

这是输出:

command is xdotool
argument is mousemove
x is 1500
y is 1500

mousemove: Unknown command: 1500
Run 'mousemove help' if you want a command list

Answer 1

组装args时，需要添加“xdotool”作为第一个参数。

从man page获得execvp:

The first argument, by convention, should point to the filename associated with the file being executed.

所以应该是char *args[] = {"xdotool", argument, x, y, nullptr};。