我正在使用GDB分析核心转储。我知道它指向“std::basic_fstream
如何在GDB提示符下将原始内存地址转换为该模板对象?
我尝试通过以下命令:
(gdb)p *('std::basic_fstream
在当前上下文中没有符号“std::basic_fstream
(gdb)p *(std::basic_fstream
表达式中语法错误,在`)0x7fae3800b280'附近。
最佳答案
I tried by below command:
大胆猜测:您的
set auto-solib-add off
中是否有~/.gdbinit
?以下示例对我来说效果很好:
cat t.cc
#include <fstream>
int main(int argc, char *argv[])
{
std::wfstream s("/dev/tty", s.out);
for (int j = 0; j < argc; j++)
s << j << " " << argv[j] << std::endl;
return 0;
}
g++ -g t.cc && gdb -q ./a.out
(gdb) b 8
Breakpoint 1 at 0x1235: file t.cc, line 8.
(gdb) run foo
Starting program: /tmp/a.out foo
0 /tmp/a.out
1 foo
Breakpoint 1, main (argc=2, argv=0x7fffffffdc28) at t.cc:8
8 return 0;
(gdb) set print static off
(gdb) p s
$1 = {<std::basic_iostream<wchar_t, std::char_traits<wchar_t> >> = {<std::basic_istream<wchar_t, std::char_traits<wchar_t> >> = {<std::basic_ios<wchar_t, std::char_traits<wchar_t> >> = ...
(gdb) p &s
$2 = (std::wfstream *) 0x7fffffffd900
(gdb) p *('std::basic_fstream<wchar_t, std::char_traits<wchar_t> >' *)0x7fffffffd900
$3 = {<std::basic_iostream<wchar_t, std::char_traits<wchar_t> >> = {<std::basic_istream<wchar_t, std::char_traits<wchar_t> >> = {<std::basic_ios<wchar_t, std::char_traits<wchar_t> >> = {<std::ios_base> = ...
您应该尝试复制上述输出。如果可以重现它,则您的工具将按预期工作,并且您需要集中精力分析
core
转储。如果上面的示例无法按预期工作,则说明您的工具链某些部分行为不当或配置错误。
我能够获得
No symbol
结果的一种方法是通过设置auto-solib-add off
:gdb -q ./a.out
Reading symbols from ./a.out...
(gdb) b 8
Breakpoint 1 at 0x1235: file t.cc, line 8.
(gdb) set auto-solib-add off
(gdb) run
Starting program: /tmp/a.out
0 /tmp/a.out
Breakpoint 1, main (argc=1, argv=0x7fffffffdc28) at t.cc:8
8 return 0;
(gdb) p &s
$1 = (std::wfstream *) 0x7fffffffd900
(gdb) p *('std::basic_fstream<wchar_t, std::char_traits<wchar_t> >' *) 0x7fffffffd900
No symbol "std::basic_fstream<wchar_t, std::char_traits<wchar_t> >" in current context.
关于c++ - GDB:如何将内存地址转换为STL对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/63884022/