python - 将C++中的数据映射到内存并以Python读取数据

Question

我在C++中将整数映射到内存(进程1)，并尝试在Python中读取它们(进程2)..

当前结果:

1)在C++中映射整数3 ==> Python(b'\ x03 \ x00 \ x00 \ x00')

2)在C++ ==> Python(b'\ x04 \ x00 \ x00 \ x00')中映射整数4，依此类推..

码:

处理1

#include <windows.h> 
#include <iostream>

using  namespace std;

void main()
{
    auto name = "new";
    auto size = 4;

    HANDLE hSharedMemory = CreateFileMapping(NULL, NULL, PAGE_READWRITE, NULL, size, name);
    auto pMemory = (int*)MapViewOfFile(hSharedMemory, FILE_MAP_ALL_ACCESS, NULL, NULL, size);

    for (int i = 0; i < 10; i++)
    {
        * pMemory = i;
        cout << i << endl;
        Sleep(1000);
    }

    UnmapViewOfFile(pMemory);
    CloseHandle(hSharedMemory);
}

处理2

import time
import mmap
bufSize = 4
FILENAME = 'new'

for i in range(10):
    data = mmap.mmap(0, bufSize, tagname=FILENAME, access=mmap.ACCESS_READ)
    dataRead = data.read(bufSize)
    print(dataRead)
    time.sleep(1)

但是，我的目标是映射一个尺寸为320 * 240的数组，但是当我尝试如下所示的简单数组时
int arr[4] = {1,2,3,4};并尝试通过* pMemory = arr;映射到内存

我收到错误“无法将int *类型的值分配给int类型的实体”和错误代码“0x80070002” ..
关于如何解决这个问题的任何想法？

P.S由于某种原因在python中将整数9映射为b'\ t \ x00 \ x00 \ x00'==>我缺少什么？

Answer 1

使用 memcpy 将阵列复制到共享内存。

#include <cstring>
#include <windows.h>

int main() {
  int array[320*240];
  const int size = sizeof(array);
  const char *name = "new";

  HANDLE hSharedMemory = CreateFileMapping(NULL, NULL, PAGE_READWRITE, NULL, size, name);
  void *pMemory = MapViewOfFile(hSharedMemory, FILE_MAP_ALL_ACCESS, NULL, NULL, size);

  std::memcpy(pMemory, array, size);

  UnmapViewOfFile(pMemory);
  CloseHandle(hSharedMemory);
}