已经为此工作了一段时间。在有两个子节点的情况下存在段错误。我不知道如何解决这个问题。我很确定其他情况是正确的,但我目前正在努力解决要删除的节点有 2 个子节点的情况。
bool BinarySearchTree::remove(BinarySearchTree::TaskItem val) {
if(!exists(val))
return false;
else{
TaskItem* cur = root;
TaskItem* parent = nullptr;
if(size == 1){ // only one node in tree
delete cur;
root = nullptr;
size--;
return true;
}
else if(*cur == val && (!cur->right || !cur->left)){// root node is target, with one child node
if(!cur->right){
root = cur->left;
delete cur;
}
else{
root = cur->right;
delete cur;
}
size--;
return true;
}
while(!(*cur==val)){
if(val.priority < cur->priority){
parent = cur;
cur = cur->left;
}
else{
parent = cur;
cur = cur->right;
}
}
if(!cur->right && !cur->left){ // no child nodes
if(parent->right == cur){
parent->right = nullptr;
delete cur;
}
else{
parent->left = nullptr;
delete cur;
}
}
else if(cur->right && cur->left){ // 2 child nodes
TaskItem* success = cur->right;
TaskItem* par_success = cur;
while(!success->left){
par_success = success;
success = success->left;
}
cur->priority = success->priority;
cur->description = success->description;
if(par_success->left == success){
par_success->left = nullptr;
}
else{
par_success->right = nullptr;
}
delete success;
}
else{// one child node
if(!cur->right){ // child node on the left
if(parent->right == cur){
parent->right = cur->left;
delete cur;
}
else{
parent->left = cur->left;
delete cur;
}
}
if(!cur->left){
if(parent->right == cur){
parent->right = cur->right;
delete cur;
}
else{
parent->left = cur->right;
delete cur;
}
}
}
size--;
return true;
}
}
最佳答案
您正在取消引用指针而不检查 null
:
while(!(*cur==val)){
if(val.priority < cur->priority){
parent = cur;
cur = cur->left;
}
else{
parent = cur;
cur = cur->right;
}
}
如果 cur->left
或 cur->right
是 null
(我想它们是指针)在 *cur
中访问它们会段错误。在这:
else if(cur->right && cur->left){ // 2 child nodes
TaskItem* success = cur->right;
TaskItem* par_success = cur;
while(!success->left){
par_success = success;
success = success->left;
}
您正在直接访问 null
指针。如果 cur->right->left
( success->left
) 是 null
您将访问 null
下一次迭代中的指针。
关于c++ - 迭代地从二叉搜索树中删除节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62871312/