我正在开发一个 Shiny 应用程序,该应用程序试图猜测用户输入的文本片段中的下一个词。为此,我加载了三个数据帧,其中包含对下一个单词的可能猜测,并使用 grepl 查找用户输入文本末尾的三元语法或二元语法匹配。我在“常规”R 中构建它时没有错误或问题,但是当将它转换为 Shiny 时,我收到此错误:
错误:评估嵌套太深:无限递归/选项(表达式=)?
正如其他 Stack Overflow 帖子所建议的那样,我摆弄了 options(expressions = ) 值,但仍然遇到错误。没有太多其他信息来指导我,并且注意到它没有问题,任何人都可以看到我哪里出错了吗?提前致谢!
对于背景,我正在运行:Win 7,64 位操作系统 | R v3.1.1 | RStudio v0.98.944
ui.R
library(shiny)
shinyUI(fluidPage(
titlePanel("Capstone: Word Guesser"),
fluidRow(
column(12,
mainPanel(
h4('Sentence Fragment'),
p('Please enter a snippet of text - with this as a start, the app will provide you 5 guesses in ranked order to complete your phrase'),
textInput('sentence', "Snippet:", value = "Enter some text and have a great"),
h4('Guesses'),
p('Below are our top five guesses for the word that completes this snippet'),
verbatimTextOutput("final.guesses")
)
)
)
))
服务器.R
options(expressions = 10000)
quad.grams <- readRDS("quadgrams.rds")
tri.grams <- readRDS("trigrams.rds")
kneser.ney <- readRDS("kneserney.rds")
library(shiny)
library(tm)
library(plyr)
library(stringi)
library(RWeka)
library(stringr)
function(input, output, clientData, session) {
observe({
sentence <- reactive({as.character(input$sentence)})
sentence <- reactive({str_replace_all(sentence(), "[[:punct:]]", "")})
sentence <- reactive({tolower(sentence())})
sentence <- reactive({scan_tokenizer(sentence())})
n <- reactive({length(sentence())})
tri.frag <- reactive({paste(sentence()[n() - 2], sentence()[n() - 1], sentence()[n()])})
bi.frag <- reactive({paste(sentence()[n() - 1], sentence()[n()])})
quad.guesses <- reactive({quad.grams[grepl(tri.frag(), quad.grams$n1.Gram) == TRUE, 2]})
tri.guesses <- reactive({tri.grams[grepl(bi.frag(), tri.grams$n1.Gram) == TRUE, 2]})
guesses <- reactive({c(quad.guesses(), tri.guesses(), kneser.ney$nGram)})
output$final.guesses <- renderPrint({guesses()[1:5]})
})
}
最佳答案
我认为您的问题出在这里(无法确定):
observe({
sentence <- reactive({as.character(input$sentence)})
sentence <- reactive({str_replace_all(sentence(), "[[:punct:]]", "")})
sentence <- reactive({tolower(sentence())})
sentence <- reactive({scan_tokenizer(sentence())})
这四行都在使 sentence
react ,每一行都依赖于它自己,input$sentence
和其他每一行都让 shiny 感到困惑一切正常。更好的解决方案是:
observe({
sentence1 <- reactive({as.character(input$sentence)})
sentence2 <- reactive({str_replace_all(sentence1(), "[[:punct:]]", "")})
sentence3 <- reactive({tolower(sentence2())})
sentence4 <- reactive({scan_tokenizer(sentence3())})
您可以删除 sentence1
行 - 我认为 input$sentence
已经是字符。如果您愿意,可以合并剩余的行,例如:
sentence <- reactive({scan_tokenizer( tolower(
str_replace_all(input$sentence, "[[:punct:]]", "") ))
})
关于R Shiny : Infinite Recursion,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27431144/