c - 为什么我的 C 程序在第二次调用函数时崩溃？

Question

我是 C 语言的初学者，我的任务是构建一个具有各种功能的程序，该程序可用于实现 Yatzy 游戏。

这仍然是一项正在进行的工作，但我已经陷入困境，当我运行它时，一切都有效，直到我在之前运行过 throwDice() 或 readDieValues() 后尝试选择运行它们中的任何一个。如果我选择多次调用 printMenu() 函数，它就会起作用。我猜问题出在 for 循环上，但我不太清楚哪里出了问题......帮忙？

#include <stdio.h>
#include <stdlib.h> // rand(), srand()
#include <time.h>    // time()

void printMenu(void);
void throwDice(int dice[], int nrOfDice, int nrOfDieValues);
void readDieValues(int dice[], int nrOfDice);
void printDice(const int dice[], int nrOfDice);
void printScores(const int dice[], int nrOfDice, int nrOfDieValues);
int isThreeOfAKind(const int dieValues[], int nrOfDieValues);



int main(void){
    //Constants-Yatzy always has 5 die with no more and no less than values 1-6
    const int nrOfDice = 5;
    const int nrOfDieValues = 6;
    int dice[nrOfDice];             //Holds the values for the die
    int choice;                     //Holds the choice that the user inputs

    //Prints the menu to the user at the beginning of the program
    //Asks the user for a number between 1 and 4. (-1 terminates the program)
    printMenu();
    printf("\nMake your choice: ");
    scanf(" %d", &choice );

    //As long as the user doesn't want to terminate the program it 
    //excecutes the request and asks for a new number

    while (choice!=-1){
        switch(choice){
            case 0:
                printMenu();
                break;
            case 1:
                throwDice(*dice, nrOfDice, nrOfDieValues);
                break;
            case 2:
                readDieValues(*dice, nrOfDice);
                break;
            case 3:
                break;
            case 4:
                break;
            default:
                printf("Invalid choice. \n");
            }
        printf("\nMake your choice: ");
        scanf(" %d", &choice );
    }
    return 0;

}

/* Function:    throwDice
 * Description: Gives the 5 die random numbers between 1 and 6.
 * Input:       Optional to give a seed to the random-function.
 * Output:      None.
 */
void throwDice(int dice[], int nrOfDice, int nrOfDieValues){
    int i;
    int seed;
    printf("Enter seed (1 gives a random seed): ");
    scanf("%d", &seed);
    // seed 1 sets the seed at "random", (uses the current time for seed)
    //any other number will be used as a direct seed 
    if (seed==1){
        srand(time(NULL));
    }else{
        srand(seed);
    }
    //Sets random values to each die
    for (i=0; i<nrOfDice; i++){
        dice[i]= (rand()%6)+1;
        printf(" %d\n", dice[i]);
    }

}

/* Function:    readDieValues
 * Description: Manually inputs values to 5 different die.
 * Input:       5 positive integers between 1 and 6.
 * Output:      None.
 */

void readDieValues(int dice[], int nrOfDice){
    int i;
    //Sets values to each die from the user input
    for(i=0; i<nrOfDice; i++){
        printf("Die: ");
        scanf(" %d", &dice[i]);
    }
}

/* Function:    printMenu
 * Description: Prints out the menu to the user.
 * Input:       None.
 * Output:      A menu with different number choices.
 */
void printMenu(void){
    printf("MENU: \n0.  Display the menu \n1.  Make a random throw \n"
           "2.  Enter die values for a throw \n3.  Display the die values for the throw \n"
           "4.  Display the score for the throw \n-1. End program \n");

    }

Answer 1

你正在像这样使用你的函数

case 1:
      throwDice(*dice, nrOfDice, nrOfDieValues);
      break;
case 2:
      readDieValues(*dice, nrOfDice);
      break;

但是dice是一个数组int dice[nrOfDice];。在函数调用中放入*dice就像放入dice[0]。

case 1:
      throwDice(dice, nrOfDice, nrOfDieValues);
      break;
case 2:
      readDieValues(dice, nrOfDice);
      break;

您需要删除骰子之前的*。