c - C中大数字的int指针函数seg错误

Question

int     *rrange(int start, int end);

有人要求我编写一个函数并使用 malloc 分配一个整数数组，并用连续的值填充它 从 end 开始到 start 结束的值(包括 start 和 end!)，然后 返回指向数组第一个值的指针。这些函数适用于小数字，当用大数字进行测试时，我得到seg failure。我认为由于达到了 int 的限制，我遇到了 seg failure 。我该如何解决这个问题？

/*- With (1, 3) you will return an array containing 3, 2 and 1
- With (-1, 2) you will return an array containing 2, 1, 0 and -1.
- With (0, 0) you will return an array containing 0.
- With (0, -3) you will return an array containing -3, -2, -1 and 0.*/

#include <stdlib.h>

int *rrange(int start, int end)
{
    int *range;
    int i;

    i = 0;
    range = (int *)malloc(sizeof(int *));
    if (end <= start)
    {
        while (end <= start)
            range[i++] = end++;
    }
    else
    {
        while (end >= start)
            range[i++] = end--;
    }
    return (range);
}

= Test 1 ===================================================
$> ./pw53y11cbachacu14eue5cab 
$> diff -U 3 user_output_test1 test1.output | cat -e

Diff OK :D
= Test 2 ===================================================
$> ./o1jrm4t3vqengizvj1tlwab4 "21" "2313" "12"
$> diff -U 3 user_output_test2 test2.output | cat -e

Diff OK :D
= Test 3 ===================================================
$> ./usl3i1tc1xv9tr1gs9n5x5vr "2147483647" "2147483640" "7"
$> diff -U 3 user_output_test3 test3.output | cat -e
--- user_output_test3   2016-06-08 16:26:16.000000000 +0200$
+++ test3.output    2016-06-08 16:26:16.000000000 +0200$
@@ -1,8 +1,8 @@$
-0$
-0$
-0$
-0$
-0$
-0$
-0$
+2147483640$
+2147483641$
+2147483642$
+2147483643$
+2147483644$
+2147483645$
+2147483646$
$

Diff KO :(
Grade: 0

= Final grade: 0         ===============================================================

Answer 1

您的问题来自于malloc:

而不是

range = (int *)malloc(sizeof(int *));

你应该写:

range = malloc(nb_of_integer_in_range * sizeof (int));

由您来计算nb_of_integer_in_range，例如:

int nb_of_integer_in_range;
if (end > start)
{
    nb_of_integer_in_range = end - start + 1;
}
else ...