我正在尝试在 TilePane 中列出图像。当我尝试创建图像 new ImageView("address");
时出现错误,地址如下:
"file:D:/Chrysanthemum.jpeg/"
以上内容在当前工作目录之外的目录中。其他图像在类路径中。
这是 scec 中的其余代码:
public class TilePaneExample extends Application {
@Override
public void start(Stage primaryStage) {
VBox root = new VBox(30);
String[] imageResources = new String[]{
//loading images
"file:D:/Chrysanthemum.jpeg/",
"ImageResources/faviicon.png",
"ImageResources/jquery-logo.png",
"ImageResources/linkedin_32.png",
"ImageResources/loading1.png",
"ImageResources/twitter.png",
"ImageResources/twitter_32.png",
"ImageResources/wp.png",};
// Pane
TilePane tilePane = new TilePane();
tilePane.setHgap(5);
tilePane.setVgap(5);
for (final String imageResource : imageResources) {
Image image = new Image(getClass().getResourceAsStream(imageResource));
ImageView imageView = new ImageView(image);
imageView.setOnMouseClicked(new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent event) {
File f = new File(imageResource);
String absolutePath = f.getAbsolutePath();
String folderPath = absolutePath.
substring(0, absolutePath.lastIndexOf(File.separator));
System.out.println(folderPath);
try {
// Desktop.getDesktop().open(new File("D:\\WAKILI\\WAKILIdb"));
Desktop.getDesktop().open(new File(folderPath));
} catch (IllegalArgumentException iae) {
System.out.println("File Not Found");
} catch (IOException ex) {
Logger.getLogger(TilePaneExample.class.getName()).log(Level.SEVERE, null, ex);
}
}
});
tilePane.getChildren().add(imageView);
}
root.getChildren().addAll(tilePane);
primaryStage.setTitle("TilePane Example");
Scene scene = new Scene(root, 300, 150);
primaryStage.setScene(scene);
primaryStage.show();
}
public static void main(String[] args) {
launch(args);
}
}
错误:
Caused by: java.lang.NullPointerException: Input stream must not be null
请帮忙。谢谢大家。
最佳答案
即使对于非类路径图像,您也正在使用 getClass().getResourceAsStream(imageResource),对于您未从类路径加载的情况,直接传递 URL 字符串:
Image image;
if(imageResource.startsWith("file:")) {
image = new Image(imageResource);
} else {
image = new Image(getClass().getResourceAsStream(imageResource));
}
关于image - 如何使用位于当前工作目录之外的目录中的图像文件创建新的 Image(),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26090399/