我有两个日期,(它们是日期时间对象)。
我怎样才能得到这两个日期之间的差异,以秒为单位?
my $givenDate1 = DateTime->new(
year => 1982,
month => 10,
day => 25,
hour => 7,
minute => 19,
second => 35,
time_zone => 'UTC',
);
my $givenDate2 = DateTime->new(
year => 1982,
month => 10,
day => 25,
hour => 7,
minute => 20,
second => 50,
time_zone => 'UTC',
);
它应该返回时差为 75 秒
最佳答案
say $givenDate2->epoch - $givenDate1->epoch;
关于perl - 如何在 perl 中以秒为单位获取日期差异,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22196731/