我需要折叠我的数据 按行 .
seq = structure(c("h", "d", "s", "s", "f", "k", "s", "s", "f", "d",
"d", "d", "l", "l", "d", "d"), .Dim = c(4L, 4L), .Dimnames = list(
NULL, c("act1.055", "act1.056", "act1.057", "act1.058")))
我的数据是这样的:
act1.055 act1.056 act1.057 act1.058
[1,] "h" "f" "f" "l"
[2,] "d" "k" "d" "l"
[3,] "s" "s" "d" "d"
[4,] "s" "s" "d" "d"
如果我做
paste(seq, collapse = "")
[1] "hdssfkssfdddlldd"
这不是我想要的。
我需要的是
hffl
dkdl
ssdd
ssdd
如果可能,在矩阵中。
最佳答案
matrix(apply(seq, 1, paste, collapse=''), ncol=1)
# [,1]
#[1,] "hffl"
#[2,] "dkdl"
#[3,] "ssdd"
#[4,] "ssdd"
关于R - 按行折叠,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31280578/