问题
如果没有继承的方法，如何获得类的所有方法的名称？
示例
def methods = MyClass.methods.collect { it.name }
println methods.each { println it }
assert ["method1_static_void", "method2_static_String", "method3_void", "method4_String"].sort() == methods.sort()
class MyClass {
public static void method1_static_void() {}
public static String method2_static_String() {}
public void method3_void() {}
private String method4_String() {}
}
预期输出
method1_static_void
method2_static_String
method3_void
method4_String
实际输出
setProperty
getProperty
super$1$wait
super$1$wait
super$1$wait
super$1$clone
getMetaClass
invokeMethod
setMetaClass
__$swapInit
method3_void
method1_static_void
method2_static_String
this$2$method4_String
this$dist$invoke$1
this$dist$set$1
this$dist$get$1
super$1$toString
super$1$notify
super$1$notifyAll
super$1$getClass
super$1$equals
super$1$hashCode
super$1$finalize
wait
wait
wait
equals
toString
hashCode
getClass
notify
notifyAll
[setProperty, getProperty, super$1$wait, super$1$wait, super$1$wait, super$1$clone, getMetaClass, invokeMethod, setMetaClass, __$swapInit, method3_void, method1_static_void, method2_static_String, this$2$method4_String, this$dist$invoke$1, this$dist$set$1, this$dist$get$1, super$1$toString, super$1$notify, super$1$notifyAll, super$1$getClass, super$1$equals, super$1$hashCode, super$1$finalize, wait, wait, wait, equals, toString, hashCode, getClass, notify, notifyAll]
Assertion failed:
assert ["method1_static_void", "method2_static_String", "method3_void", "method4_String"] == methods
| |
| [setProperty, getProperty, super$1$wait, super$1$wait, super$1$wait, super$1$clone, getMetaClass, invokeMethod, setMetaClass, __$swapInit, method3_void, method1_static_void, method2_static_String, this$2$method4_String, this$dist$invoke$1, this$dist$set$1, this$dist$get$1, super$1$toString, super$1$notify, super$1$notifyAll, super$1$getClass, super$1$equals, super$1$hashCode, super$1$finalize, wait, wait, wait, equals, toString, hashCode, getClass, notify, notifyAll]
false
Google 调查结果
最佳答案
代替:
def methods = MyClass.methods.collect { it.name }
您只需要声明的非合成方法:
def methods = MyClass.declaredMethods.findAll { !it.synthetic }.name
关于reflection - 如何使用 Groovy 获取没有继承方法的类的所有方法名称？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/22065290/