我在尝试什么
我有 2 个数组，如下所示:
数组 1:
Array
(
[38] => Array
(
[0] => Array
(
[code] => ACC
[amount] => 50
[emp_number] => 38
)
[1] => Array
(
[code] => CAR
[amount] => 60
[emp_number] => 38
)
)
[22] => Array
(
[0] => Array
(
[code] => ACC
[amount] => 110
[emp_number] => 22
)
[1] => Array
(
[code] => AIR
[amount] => 260
[emp_number] => 22
)
[2] => Array
(
[code] => CAP
[amount] => 205
[emp_number] => 22
)
)
)
数组 2:
Array
(
[0] => Array
(
[code] => ACC
)
[1] => Array
(
[code] => AIR
)
[2] => Array
(
[code] => ARC
)
[3] => Array
(
[code] => ATV
)
[4] => Array
(
[code] => CAP
)
[5] => Array
(
[code] => CAR
)
)
我想要什么
最终数组:
Array
(
[38] => Array
(
[0] => Array
(
[code] => ACC
[amount] => 50
[emp_number] => 38
)
[1] => Array
(
[code] => AIR
[amount] => ''
[emp_number] => 38
)
[2] => Array
(
[code] => ARC
[amount] => ''
[emp_number] => 38
)
[3] => Array
(
[code] => ATV
[amount] => ''
[emp_number] => 38
)
[4] => Array
(
[code] => CAP
[amount] => ''
[emp_number] => 38
)
[5] => Array
(
[code] => CAR
[amount] => 60
[emp_number] => 38
)
)
[22] => Array
(
[0] => Array
(
[code] => ACC
[amount] => 110
[emp_number] => 22
)
[1] => Array
(
[code] => AIR
[amount] => 260
[emp_number] => 22
)
[2] => Array
(
[code] => ARC
[amount] => ''
[emp_number] => 22
)
[3] => Array
(
[code] => ATV
[amount] => ''
[emp_number] => 22
)
[4] => Array
(
[code] => CAP
[amount] => 205
[emp_number] => 22
)
[5] => Array
(
[code] => CAR
[amount] => ''
[emp_number] => 22
)
)
)
代码
$count = count($category);
$exp = array();
foreach ($expItem as $empItem) {
$j = 0;
foreach ($category as $cat) {
foreach ($empItem as $emp) {
for ($k = 0; $k < $count; $k++) {
if ($emp['code'] == $category['code']) {
$expItem[$emp['emp_number']][$k]['name'] = $category[$k]['name'];
} else {
$expItem[$emp['emp_number']][$k]['code'] = $category[$k]['code'];
$expItem[$emp['emp_number']][$k]['name'] = $category[$k]['name'];
}
}
}
$j++;
}
}
此处 $expItem 是第一个数组，$category 是第二个数组，我在 $expItem 本身中获取最终数组。 $emp['emp_number'] 是第一个数组“38”和“22”的单元键。它与 code 和 amount 一起在第一个数组中可用。 $category 还包含值 name
如何组合这两个数组才能正确得到最终数组？
编辑: 第一个数组中的代码与第二个数组中的代码相同。第二个数组包含所有代码和各自的名称。第一个数组显示员工数据，其中显示员工使用的代码数量。我想要的是，如果员工没有使用任何代码，那么第一个数组应该在员工数据中显示相应的代码和金额为 0。代码是动态实现的，因此不能对其进行硬编码。
最佳答案
你能试试这个吗？ $result 将具有预期的数组。
$result = [];
foreach($expItem as $key => $item) {
$result[$key] = array_map(function($value) use ($key, $item){
$value['amount'] = '';
$value['emp_number'] = $key;
foreach($item as $_key => $_item) {
if($_item['code'] === $value['code']) {
$value['amount'] = $_item['amount'];
}
}
return $value;
}, $category);
}
关于php - 在php中组合多维数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/33934450/