我正在尝试删除具有给定类的每个节点。
查找我使用的元素:
$xpath = new DOMXPath($dom);
foreach( $xpath->query('//div[contains(attribute::class, "foo")]') as $e ) {
// Delete this node
}
但是,如何删除此foreach循环中的元素?
编辑:顺便说一句:我如何首先检查DOM中是否存在带有“foo”类的元素(在开始循环之前)?
更新:
这是我的HTML:
<div class="main">
<div class="delete_this" contenteditable="true">Target</div>
<div class="class1"></div>
<div class="content"><p>Anything</p></div>
</div>
这对于上面的示例不起作用:
$xpath = new DOMXPath($dom);
foreach( $xpath->query('//div[contains(attribute::class, "delete_this")]') as $e ) {
$e->parentNode->removeChild($e);
}
最佳答案
您需要使用父元素的removeChild()
方法:
$xpath = new DOMXPath($dom);
foreach($xpath->query('//div[contains(attribute::class, "foo")]') as $e ) {
// Delete this node
$e->parentNode->removeChild($e);
}
顺便说一句,关于您的第二个问题,如果没有找到任何元素,则该循环根本不会迭代。
这是一个工作示例:
$html = <<<EOF
<div class="main">
<div class="delete_this" contenteditable="true">Target</div>
<div class="class1"></div>
<div class="content"><p>Anything</p></div>
</div>
EOF;
$doc = new DOMDocument();
$doc->loadHTML($html);
$selector = new DOMXPath($doc);
foreach($selector->query('//div[contains(attribute::class, "delete_this")]') as $e ) {
$e->parentNode->removeChild($e);
}
echo $doc->saveHTML($doc->documentElement);
关于php - PHP DOMDocument:按类删除元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25524217/