需要创建一个如下所示的图表:
我快到了，只是缺少垂直绘制的各个点。
这里是数据:
q6 <- structure(list(x1 = c(0.0629, 0.063, 0.0628, 0.0634, 0.0619,
0.0613, 0.063, 0.0628, 0.0623, 0.0631, 0.0635, 0.0623, 0.0635,
0.0645, 0.0619, 0.0631, 0.0616, 0.063, 0.0636, 0.064, 0.0628,
0.0615, 0.063, 0.0635, 0.0623), x2 = c(0.0636, 0.0631, 0.0631,
0.063, 0.0628, 0.0629, 0.0639, 0.0627, 0.0626, 0.0631, 0.063,
0.063, 0.0631, 0.064, 0.0644, 0.0627, 0.0623, 0.063, 0.0631,
0.0635, 0.0625, 0.0625, 0.0632, 0.0629, 0.0629), x3 = c(0.064,
0.0622, 0.0633, 0.0631, 0.063, 0.0634, 0.0625, 0.0622, 0.0633,
0.0633, 0.0638, 0.063, 0.063, 0.0631, 0.0632, 0.063, 0.0631,
0.0626, 0.0629, 0.0629, 0.0616, 0.0619, 0.063, 0.0635, 0.063),
x4 = c(0.0635, 0.0625, 0.0633, 0.0632, 0.0619, 0.0625, 0.0629,
0.0625, 0.063, 0.0631, 0.0635, 0.0627, 0.063, 0.064, 0.0622,
0.0628, 0.062, 0.0629, 0.0635, 0.0635, 0.062, 0.0619, 0.0631,
0.0631, 0.0626), x5 = c(0.064, 0.0627, 0.063, 0.0633, 0.0625,
0.0628, 0.0627, 0.0627, 0.0624, 0.063, 0.0633, 0.0629, 0.063,
0.0642, 0.0635, 0.0629, 0.0625, 0.0628, 0.0634, 0.0634, 0.0623,
0.0622, 0.063, 0.0633, 0.0628)), .Names = c("x1", "x2", "x3",
"x4", "x5"), class = "data.frame", row.names = c(NA, -25L))
代码如下:
range_span <- function(x) return(diff(range(x))) # function to calculate range
# q6 <- read.table(file="/Users/.../blah.csv",header=T,sep=",") #data
medians <- apply(q6,1,median)
ranges <- apply(q6,1,range_span)
centre <- mean(medians) #grand median
Rtilde <- median(ranges) #median of ranges
plot(medians, type="b",xaxp=c(1, 25, 24),pch=19,xlab="Sample No.",ylab="Medians",main="Median Chart for Thickness of Metal Parts")
# code below draws the control limits
action.limits<-c(centre+0.681*Rtilde,centre-0.681*Rtilde)
warn.limits<-c(centre+(2/3)*0.681*Rtilde,centre-(2/3)*0.681*Rtilde)
abline(h = centre, lty = 3, col = "black")
v0 <-c("CL")
mtext(side = 4, text = v0, at = centre, col = "black", las=2)
abline(h = warn.limits, lty = 3, col = "blue")
v1 <-c("UWL","LWL")
mtext(side = 4, text = v1, at = warn.limits, col = "blue", las=2)
abline(h = action.limits, lty = 3, col = "black")
v2 <-c("UCL","LCL") # the labels for action.limits
mtext(side = 4, text = v2, at = action.limits, col = "black", las=2)
我确信有一个简单的解决方案，我对 R 一点经验都没有。我只是想通过在 R 中为类(class)作业制作图表来给自己一个挑战，但现在我开始没时间了。
points()有帮助吗？我需要 R 来识别 q6 中的每一行都是一个样本，这样我就可以做points(q6,c(1:25))或类似的事情？
最佳答案
因此，您的数据中的任何位置都没有 x 坐标(1 到 25)，这会使绘图变得困难。
q6$x = 1:25
下一步并不是绝对必要的，但它使事情变得更方便。我要把你的数据“融合”成长格式:
q6_long = reshape2::melt(q6, id.vars = "x")
## just showing what it looks like now
head(q6_long)
# x variable value
# 1 1 x1 0.0629
# 2 2 x1 0.0630
# 3 3 x1 0.0628
# 4 4 x1 0.0634
# 5 5 x1 0.0619
# 6 6 x1 0.0613
现在使用 points 函数可以轻松添加点:
points(q6_long$x, q6_long$value, pch = 5)
关于r - 如何在 R 中的中值控制图的垂直线上绘制点，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/34949996/