我想从今天起最后一个星期六 + 21 天。
为了实现这一点,我编写了如下所示的脚本。但问题是我无法成功从结果中返回值。
我想在 SQL Server 中创建这个函数,并将在我想要的存储过程中获取这个值。
DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
DECLARE @NumOfDays INT
DECLARE @resultDate smalldatetime
SET @StartDate = GETDATE()
SET @EndDate = GETDATE()+21
SET @NumOfDays = DATEDIFF(DD,@StartDate , @EndDate) + 1 ;
WITH Tens AS
(
SELECT 1 N UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1
),
HUNDREDS AS
(
SELECT T1.N FROM TENS T1 CROSS JOIN TENS T2
),
THOUSANDS AS
(
SELECT T1.N FROM HUNDREDS T1 CROSS JOIN HUNDREDS T2
),
Numbers AS
(
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT 0)) RN FROM THOUSANDS
)
SELECT TOP 1
DATEADD(DD, (RN - 1), @StartDate) SaturdayDates
FROM
Numbers
WHERE
RN <= @NumOfDays
AND DATENAME (WEEKDAY, (DATEADD(DD, (RN - 1), @StartDate))) = 'Saturday'
ORDER BY
SaturdayDates DESC
你能指导我实现我的目标吗?谢谢
最佳答案
就这样改写表值函数 :
CREATE FUNCTION dbo.Get_NextSaturdayDay()
RETURNS TABLE
AS
RETURN
(
-- Add the SELECT statement with parameter references here
WITH Tens AS
(
SELECT 1 N UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1
),
HUNDREDS AS
(
SELECT T1.N FROM TENS T1 CROSS JOIN TENS T2
),
THOUSANDS AS
(
SELECT T1.N FROM HUNDREDS T1 CROSS JOIN HUNDREDS T2
),
Numbers AS
(
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT 0)) RN FROM THOUSANDS
)
SELECT TOP 1 DATEADD( DD,(RN - 1) , GETDATE() ) as SaturdayDates
FROM
Numbers
WHERE
RN <= (DATEDIFF(DD,GETDATE() , DATEADD(day,21,GETDATE()) ) + 1) AND DATENAME ( WEEKDAY, (DATEADD( DD,(RN - 1) , GETDATE() )) ) = 'Saturday'
ORDER BY SaturdayDates DESC
)
GO
比做:
SELECT *
FROM dbo.Get_NextSaturdayDay()
输出:
SaturdayDates
2016-10-15 11:02:33.570
如果您需要 标量值函数 :
CREATE FUNCTION dbo.Get_NextSaturdayDay ()
RETURNS datetime
AS
BEGIN
DECLARE @datetime datetime
;WITH Tens AS
(
SELECT 1 N UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 1
),
HUNDREDS AS
(
SELECT T1.N FROM TENS T1 CROSS JOIN TENS T2
),
THOUSANDS AS
(
SELECT T1.N FROM HUNDREDS T1 CROSS JOIN HUNDREDS T2
),
Numbers AS
(
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT 0)) RN FROM THOUSANDS
)
SELECT TOP 1 @datetime = DATEADD( DD,(RN - 1) , GETDATE() )
FROM
Numbers
WHERE
RN <= (DATEDIFF(DD,GETDATE() , DATEADD(day,21,GETDATE()) ) + 1) AND DATENAME ( WEEKDAY, (DATEADD( DD,(RN - 1) , GETDATE() )) ) = 'Saturday'
ORDER BY DATEADD( DD,(RN - 1) , GETDATE() ) DESC
-- Return the result of the function
RETURN @datetime
END
GO
然后运行:
SELECT dbo.Get_NextSaturdayDay()
输出:
2016-10-15 11:02:33.570
关于sql-server - SQL Server 函数的返回值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39786353/