我的查询看起来像这样 -
@Override
public Page<Country> findPaginatedCountries(String country, Optional<String> status, Pageable pageable) {
QCountry qCountry= QCountry.someObject;
QActiveCountry qActiveCountry = QActiveCountry.activeCountry;
JPAQuery jpaQuery = new JPAQuery(entityManager);
QueryBase queryBase = jpaQuery.from(qCountry).innerJoin(qActiveCountry).fetch()
.where(qCountry.codeLeft.country.upper().eq(country.toUpperCase()))
.where(qCountry.codeRight.country.upper().eq(country.toUpperCase()));
if(status.isPresent()){
queryBase = queryBase.where(qActiveCountry.id(qCountry.active.id))
.where(qActiveCountry.status.upper().eq(status.get().toUpperCase()));
}
.......}
我可以改写一个谓词,这会导致相同的响应吗?
Predicate predicate= qCountry.id.eq(qActiveCountry.id).and(qCountry.codeLeft.country.upper().eq(country.toUpperCase())).and(qCountry.codeRight.country.upper().eq(country.toUpperCase()));
最佳答案
是的你可以。似乎您正在使用 Spring Data。只需创建一个新的存储库接口(interface),或使用 QueryDslPredicateExecutor 扩展现有的 JPARepository 类型接口(interface),例如:
@Repository
public interface CountryRepository extends JpaRepository<Country, Long>,
QueryDslPredicateExecutor<Country>
现在你可以像这样传递你的谓词:
Predicate countryExpression= qCountry.id.eq(qActiveCountry.id).and(qCountry.codeLeft.country.upper().eq(country.toUpperCase())).and(qCountry.codeRight.country.upper().eq(country.toUpperCase()));
CountryRepository.findAll(countryExpression, pageable);
关于querydsl - 如何将涉及连接的 JPAQuery 对象转换为谓词?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42501147/