我正在尝试构建一个 restfull API,我认为,REST 对此不是很明确,一个资源应该可以通过多个 URL 访问。让我举个例子。
Route::group(['prefix' => 'forum'], function(){
Route::resource('categories', 'CategoriesController');
Route::resource('categories.discussions', 'DiscussionsController');
Route::resource('discussions', 'DiscussionsController');
});
我的意图是能够通过将讨论附加到它所属的类别来访问每个讨论:
localhost/forum/categories/{category_id}/discussions
或通过此网址
本地主机/论坛/讨论
有没有人能在不重写整个 Controller 的情况下使用这样的东西。
这是我的讨论 Controller :
class DiscussionsController extends ApiController {
public function __construct(DiscussionRepositoryInterface $discussion)
{
$this->discussions = $discussion;
}
/**
* Display a listing of the resource.
*
* @return Response
*/
public function index($category = null)
{
$response = $this->discussions->all($category);
return $this->respond($response->getData());
}
/**
* Show the form for creating a new resource.
*
* @return Response
*/
public function create()
{
if (!$this->hasPermission('forum.create.discussion'))
{
return $this->respondNotAllowed();
}
return $this->respondSuccess('Granted');
}
/**
* Store a newly created resource in storage.
*
* @return Response
*/
public function store($category)
{
if (!$this->hasPermission('forum.create.discussion'))
{
return $this->respondNotAllowed();
}
return $this->respondSuccess('Granted');
}
/**
* Display the specified resource.
*
* @param int $id
* @return Response
*/
public function show($categories = null, $discussions)
{
$discussion = $this->discussions->find($categories, $discussions);
if ($discussion == null)
return $this->respondNotFound('Discussion not found');
$data = [
'discussions' => $discussion
];
return $this->respond($data);
}
/**
* Show the form for editing the specified resource.
*
* @param int $id
* @return Response
*/
public function edit($id)
{
if (!$this->hasPermission('forum.edit.discussion'))
{
return $this->respondNotAllowed();
}
return $this->respondSuccess('Granted');
}
/**
* Update the specified resource in storage.
*
* @param int $id
* @return Response
*/
public function update($id, $data)
{
if (!$this->hasPermission('forum.edit.discussion'))
{
return $this->respondNotAllowed();
}
$data = Input::only('category_id', 'user_id', 'desc', 'title');
$data = $this->clearNullInput($data);
if ($this->discussions->update($id, $data))
return $this->respondError('Couldnt update discussion');
return $this->respondSuccess('Discussion updated successfully');
}
/**
* Remove the specified resource from storage.
*
* @param int $id
* @return Response
*/
public function destroy($id)
{
if (!$this->hasPermission('forum.delete.discussion'))
{
return $this->respondNotAllowed();
}
if (!$this->discussions->delete($id))
return $this->respondError('Couldnt destroy user');
return $this->respondSuccess('Granted');
}
}
index 方法在两个调用中都有效(localhost/forum/categories/id/discussions 和 localhost/forum/discussions)
但是当我尝试显示资源时,只有长版本有效,短版本会抛出以下异常:
ErrorException in DiscussionsController.php line 68:
Missing argument 2 for App\Http\Controllers\DiscussionsController::show()
我会说 Laravel 变得疯狂,因为他无法识别 ID,是否有任何聪明的解决方法,或者我是否必须重写 Controller ?
非常感谢任何意见,谢谢
最佳答案
你可以试试这样的东西
public function show(Category $category, Discussion $discussion)
如果您正在调用 localhost/forum/categories/{categories}/discussions/{discussions}
那么两个变量都有它们的确切值。如果你调用 localhost/forum/discussions/{discussions}
然后类别将只是新类别
确保将 RouteServiceProvider 中的值绑定(bind)为
$router->model('discussions', 'App\Discussion');
$router->model('categories', 'App\Category');
关于php - 多个路由到同一个 Controller ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29791311/