VHDL 标识符的正则表达式

Question

我正在尝试解析我的 VHDL 代码以进行一些额外的检查。

我正在寻找一个正则表达式来检查 VHDL 中的相关标识符。而且我对正则表达式还很陌生。

它有以下规则:

只能包含字母 (A..Z a..z) 数字 (0..9) 和下划线 ('_')

必须以 和 字母开头

不得以下划线字符结尾

不能包含两个连续的下划线字符

所以我目前的问题是检查两个连续的下划线字符......

更新:我想我只是自己回答了这个问题......请仔细检查

[A-Za-z](_?[A-Za-z0-9])*

Answer 1

(?!.*__)[a-zA-Z][\w]*[^_]

这应该可以解决问题。

说明:

 # (?!.*__)[a-zA-Z][\w]*[^_]
# 
# Assert that it is impossible to match the regex below starting at this position (negative lookahead) «(?!.*__)»
#    Match any single character that is not a line break character «.*»
#       Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
#    Match the characters “__” literally «__»
# Match a single character present in the list below «[a-zA-Z]»
#    A character in the range between “a” and “z” «a-z»
#    A character in the range between “A” and “Z” «A-Z»
# Match a single character that is a “word character” (letters, digits, etc.) «[\w]*»
#    Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
# Match any character that is NOT a “_” «[^_]»