在 php 中,给定一个纬度和经度点、一个方位角(以度为单位)和一个距离(以英尺或公里或其他单位为单位)我如何计算出新的经纬度点是什么?这是我尝试过的方法,但这是错误的。
function destinationPoint($lat, $lng, $brng, $dist) {
$meters = $dist/3.2808399; // dist in meters
$dist = $meters/1000; // dist in km
$rad = 6371; // earths mean radius
$dist = $dist/$rad; // convert dist to angular distance in radians
$brng = deg2rad($brng); // conver to radians
$lat1 = deg2rad($lat);
$lon1 = deg2rad($lng);
$lat2 = asin(sin($lat1)*cos($dist) + cos($lat1)*sin($dist)*cos($brng) );
$lon2 = $lon1 + atan2(sin($brng)*sin($dist)*cos($lat1),cos($dist)-sin($lat1)*sin($lat2));
$lon2 = ($lon2+3*M_PI) % (2*M_PI) - M_PI; // normalise to -180..+180º
$lat2 = rad2deg($lat2);
$lon2 = rad2deg($lon2);
echo "lat2 = ".$lat2."<br/>";
echo "lon2 = ".$lon2."<br/>";
}
最佳答案
改变
$lon2 = ($lon2+3*M_PI) % (2*M_PI) - M_PI;
到
$lon2 = fmod($lon2 + 3*M_PI, 2*M_PI) - M_PI;
根据 PHP's documentation about the modulus operator (%
) ,
Operands of modulus are converted to integers (by stripping the decimal part) before processing.
fmod “[r] 返回参数除法的浮点余数(模)。”
关于php - 在给定初始经纬度、距离和方位角的情况下,在 php 中查找经纬度点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11111077/