package com.techm.template;
import java.sql.Types;
import java.util.Date;
import java.util.HashMap;
import java.util.Map;
import javax.sql.DataSource;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.namedparam.MapSqlParameterSource;
import org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate;
import org.springframework.jdbc.core.namedparam.SqlParameterSource;
import org.springframework.jdbc.datasource.DriverManagerDataSource;
public class InsertRecordInDatabaseWithJdbcTemplate {
private static final String driverClassName = "oracle.jdbc.driver.OracleDriver";
private static final String url = "jdbc:oracle:thin:@localhost:1521:xe";
private static final String dbUsername = "SYSTEM";
private static final String dbPassword = "9848451415";
private static final String sql = "INSERT INTO employee(firstname,lastname,username,password) VALUES(?,?,?,?)";
private static DataSource dataSource;
public static void main(String[] args) throws Exception {
dataSource = getDataSource();
Employee e = new Employee();
e.setFirstname("Surya Teja");
e.setLastname("Tammana");
e.setUsername("surya_kvm");
e.setPassword("9848451415");
int result = saveRecord(e);
if(result != 0){
System.out.println("Success");
}
else{
System.out.println("Failure");
}
}
public static int saveRecord(Employee e) {
NamedParameterJdbcTemplate template = new NamedParameterJdbcTemplate(dataSource);
SqlParameterSource params = new MapSqlParameterSource();
Map<String, Object> parameters = new HashMap<String, Object>();
parameters.put("firstnames", e.getFirstname());
parameters.put("lastname", e.getLastname());
parameters.put("username", e.getUsername());
parameters.put("password", e.getPassword());
int result = template.update(sql, parameters);
return result;
}
public static DriverManagerDataSource getDataSource() {
DriverManagerDataSource dataSource = new DriverManagerDataSource();
dataSource.setDriverClassName(driverClassName);
dataSource.setUrl(url);
dataSource.setUsername(dbUsername);
dataSource.setPassword(dbPassword);
return dataSource;
}
}
员工.java
package com.techm.template;
public class Employee {
private String firstname;
private String lastname;
private String username;
private String password;
public String getFirstname() {
return firstname;
}
public void setFirstname(String firstname) {
this.firstname = firstname;
}
public String getLastname() {
return lastname;
}
public void setLastname(String lastname) {
this.lastname = lastname;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
}
控制台
2017 年 1 月 22 日上午 12:25:24 org.springframework.jdbc.datasource.DriverManagerDataSource setDriverClassName 信息:加载的 JDBC 驱动程序:oracle.jdbc.driver.OracleDriver 线程“main”中的异常 org.springframework.dao.InvalidDataAccessApiUsageException:SQL [INSERT INTO employee(firstname,lastname,username,password) VALUES(?,?,?,?)]: 给定 4 个参数但预期为 0 在 org.springframework.jdbc.core.PreparedStatementCreatorFactory$PreparedStatementCreatorImpl.(PreparedStatementCreatorFactory.java:221) 在 org.springframework.jdbc.core.PreparedStatementCreatorFactory$PreparedStatementCreatorImpl.(PreparedStatementCreatorFactory.java:199) 在 org.springframework.jdbc.core.PreparedStatementCreatorFactory.newPreparedStatementCreator(PreparedStatementCreatorFactory.java:173) 在 org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate.getPreparedStatementCreator(NamedParameterJdbcTemplate.java:351) 在 org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate.update(NamedParameterJdbcTemplate.java:287) 在 org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate.update(NamedParameterJdbcTemplate.java:292) 在 com.techm.template.InsertRecordInDatabaseWithJdbcTemplate.saveRecord(InsertRecordInDatabaseWithJdbcTemplate.java:64) 在 com.techm.template.InsertRecordInDatabaseWithJdbcTemplate.main(InsertRecordInDatabaseWithJdbcTemplate.java:40)
最佳答案
您在 SQL 查询中使用了位置参数。这不起作用,因为您正在使用需要命名参数的 NamedParameterJdbcTemplate
。只需修改您的查询以使用这样的命名参数:
"INSERT INTO employee(firstname, lastname, username, password) VALUES(:firstname, :lastname, :username, :password)"
您也可以使用 Employee 对象作为参数源:
public static int saveRecord(Employee e) {
NamedParameterJdbcTemplate template = new NamedParameterJdbcTemplate(dataSource);
SqlParameterSource params = new BeanPropertySqlParameterSource(e);
int result = template.update(sql, params);
return result;
}
BeanPropertySqlParameterSource
将使用 Employees 属性来设置参数。
关于spring - 使用 NamedParameterJdbcTemplate 向 DataBase 发送数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41783375/