string - 如何在Go中将文本位字符串转换为IP地址

Question

我可以使用Sprintf将net.IP地址转换为位串:

fmt.Sprintf("%08b%08b%08b%08b",net.IP[0],net.IP[1],net.IP[2],net.IP[3])

如何从字符串"11000000101010000000000000000000"转换回"192.168.0.0"？
谢谢

Answer 1

func binaryStringToIPv4(bs string) (uint8, uint8, uint8, uint8) {
    var ip uint32

    for i, c := range bs {
        // 31 = len(bs)-1
        ip |= uint32(byte(c)-'0') << (31 - i)
    }
    return uint8(ip >> 24), uint8(ip >> 16), uint8(ip >> 8), uint8(ip)
}