json - 使用数组转换JSON

Question

我已经编写了以下代码来从JSON获取数组，并希望检索类似

[{{id“:” id1“，” friendly“:” friendly1“}，{” id“:” id2“，” friendly“:” friendly2“}}

但它是空的:

[{“id”:“”，“友好”:“”}，{“id”:“”，“友好”:“”}]

package main

import (
    "encoding/json"
    "fmt"
)

var input = `[
            {
                "not needed": "",
                "_source": {
                    "id": "id1",
                    "friendly": "friendly1"
                }
            },
            {
                "_source": {
                    "id": "id2",
                    "friendly": "friendly2"
                }
            }]`

type source struct {
    Id string `json:"id"`
    Friendly string `json:"friendly"`
}

func main() {
    result := make([]source, 0)
    sources := []source{}

    json.Unmarshal([]byte(input), &sources)

    for _, n := range sources {
        result = append(result, n)
    }
    out, _ := json.Marshal(result)
    fmt.Println(string(out))
}

Answer 1

尝试创建另一个结构，该结构具有一个称为Source类型的source的字段。在下面的示例中，我将此结构称为outer。您的输入应该是outer数组，结果应该是source数组。

像这样:

import (
    "encoding/json"
    "fmt"
)

var input = `[
            {
                "not needed": "",
                "_source": {
                    "id": "id1",
                    "friendly": "friendly1"
                }
            },
            {
                "_source": {
                    "id": "id2",
                    "friendly": "friendly2"
                }
            }]`

type outer struct {
    Source source `json:"_source"`
}

type source struct {
    Id string `json:"id"`
    Friendly string `json:"friendly"`
}

func main() {
    result := make([]source, 0)
    sources := []outer{}

    json.Unmarshal([]byte(input), &sources)

    for _, n := range sources {
        result = append(result, n.Source)
    }
    out, _ := json.Marshal(result)
    fmt.Println(string(out))
}```