我有两个结构。一种是抽奖,一种是奖励。我使用的是Mysql数据库。我想从数据库读取数据并以 JSON 格式写入。我可以做到这一点,但我想要一个嵌套结构,我想在 Lottery 结构中迭代 Reward 结构。我可以这样做吗?
这是我的彩票和奖励结构
type Lottery struct{
Id int `json:"lottery_id"`
Lottery string `json:"lottery_name"`
Description string `json:"lottery_description"`
Reward []Rew `json:"rewards"`
}
type Rew struct{
Id int `json:"reward_id"`
RewardName string `json:"reward_name"`
Description string `json:"reward_description"`
Asset int `json:"reward_asset"`
AssetName string `json:"reward_asset_name"`
}
这是我的代码
app.Get("/lottery/{id:int}", func (ctx iris.Context){
id1 := ctx.Params().GetIntDefault("id",0)
stmtOut, err := db.Prepare("select lottery_name, lottery_description from lottery_table where id = ?")
if err !=nil{
panic(err.Error())
}
defer stmtOut.Close()
var lottery_name, lottery_description string
err1 := stmtOut.QueryRow(id1).Scan(&lottery_name,&lottery_description)
if err != nil{
panic(err1.Error())
}
stmtOut1, err := db.Query("select id, reward_name, reward_description, reward_asset, reward_asset_name from rewards_table where lottery_id = ?",id1)
if err != nil{
panic(err.Error())
}
defer stmtOut1.Close()
for stmtOut1.Next() {
var id, reward_asset int
var reward_name, reward_description, reward_asset_name string
err2 := stmtOut1.Scan(&id, &reward_name, &reward_description, &reward_asset, &reward_asset_name)
if err2 != nil {
panic(err.Error())
}
rew := Lottery{
Id: id1,
Lottery: lottery_name,
Description: lottery_description,
Reward : []Rew{Rew{
Id: id,
RewardName: reward_name,
Description: reward_description,
Asset: reward_asset,
AssetName: reward_asset_name,
},
},
}
ctx.JSON(&rew)
}
})
当我使用上述函数时,我得到这样的 JSON 格式
{
"lottery_id": 7,
"lottery_name": "lottery2",
"lottery_description": "lottery for 7",
"rewards": [
{
"reward_id": 9,
"reward_name": "Reward3",
"reward_description": "Reward for lottery 7",
"reward_asset": 20,
"reward_asset_name": "AC"
}
]
}{
"lottery_id": 7,
"lottery_name": "lottery2",
"lottery_description": "lottery for 7",
"rewards": [
{
"reward_id": 10,
"reward_name": "Reward5",
"reward_description": "Reward for lottery 7",
"reward_asset": 15,
"reward_asset_name": "AC"
}
]
}
但是我想将 JSON 获取为
{
"lottery_id":7,
"lottery_name":"lottery2"
"lottery_description":"lottery for 7"
"rewards":[
{
"reward_id":9,
"reward_name": "Reward3",
"reward_description": "Reward for lottery 7",
"reward_asset": 20,
"reward_asset_name": "ABC"
},
{ "reward_id":10,
"reward_name": "Reward5",
"reward_description": "Reward for lottery 7",
"reward_asset": 15,
"reward_asset_name": "ABC"
},
{ "reward_id":11,
"reward_name": "Reward7",
"reward_description": "Reward for lottery 7",
"reward_asset": 10,
"reward_asset_name": "ABC"
}
]
}
如何在结构体中进行迭代?结构体中是否可以有 for 循环?或者还有其他方法可以获取上面的 JSON 吗?
请帮助我。
最佳答案
类似这样的事情:
app.Get("/lottery/{id:int}", func(ctx iris.Context) {
id1 := ctx.Params().GetIntDefault("id", 0)
stmtOut, err := db.Prepare("select lottery_name, lottery_description from lottery_table where id = ?")
if err != nil {
panic(err.Error())
}
defer stmtOut.Close()
lot := Lottery{Id: id1}
err1 := stmtOut.QueryRow(id1).Scan(&lot.Lottery, &lot.Description)
if err != nil {
panic(err1.Error())
}
stmtOut1, err := db.Query("select id, reward_name, reward_description, reward_asset, reward_asset_name from rewards_table where lottery_id = ?", id1)
if err != nil {
panic(err.Error())
}
defer stmtOut1.Close()
for stmtOut1.Next() {
rew := Rew{}
err2 := stmtOut1.Scan(&rew.Id, &rew.RewardName, &rew.Description, &rew.Asset, &rew.AssetName)
if err2 != nil {
panic(err.Error())
}
lot.Reward = append(lot.Reward, rew)
}
ctx.JSON(lot)
})
关于for-loop - 如何在 Golang 中迭代结构中的 slice 或者是否可以在结构中使用 for 循环?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62400721/