go - YAML Unmarshal map [string] struct

Question

我绝对不明白这一点。这是给定的Yaml文件

items:
  - item1:
      one: "some"
      two: "some string"
  - item2:
      one: "some"
      two: "some string"

和一个配置:

type Item struct {
    one string
    two string
}
type conf struct {
    Items map[string]Item
}

func (c *conf) getConfig(filename string) *conf {

    yamlFile, err := ioutil.ReadFile(filename)
    if err != nil {
        log.Printf("yamlFile.Get err   #%v ", err)
    }
    err = yaml.Unmarshal(yamlFile, &c)
    if err != nil {
        log.Fatalf("Unmarshal: %v", err)
    }

    //c.Items = make(map[string]Items)
    return c
}

我正在使用gopkg.in/yaml.v2
出现此错误:

Unmarshal: yaml: unmarshal errors:
  line 6: cannot unmarshal !!seq into map[string]application.Item

请帮助我了解我在这里做错了什么。我已经到处搜索了。
提前致谢。

Answer 1

首先，您需要将YAML更改为

  items:
      item1:
        one: "some"
        two: "some string"
      item2:
        one: "some"
        two: "some string"

然后，在您的代码中

type Config struct {
    Items map[string]Item
}

type Item struct {
    One string
    Two string
}

然后用

fmt.Printf("%+v\n", c.Items)

你将会有

map[item1:{One:some Two:some string} item2:{One:some Two:some string}]