dictionary - 将map [string] [] string转换为yaml结构

Question

我尝试像这样将make(map [string] string)转换为 yaml :

Yaml输出需求:

items:
    keys1:value1
    keys2:value2
    keys3:value3
    keys4:value4

键，值是此listKey字符串映射。 J =字符串= {“” key1“:” value1“，” key2“:” value2“}

type Items struct {
 items string
 ItemsValues map[string][]string
 }

func ConvertToYelm(j string){
y := Items{}

var dataJson map[string]string
err := json.Unmarshal([]byte(j), &dataJson)
if err != nil {
    fmt.Println(err)
    return
}
listKey := make(map[string]string)

for k := range dataJson{
   listKey[k] = k
}

yelm, err := yaml.Marshal(listKey)
if err != nil {
   fmt.Println(err)
   return
}
err = yaml.Unmarshal(yelm, Items)
if err != nil {
    fmt.Println(err)
    return
}
yeml2, err := yaml.Marshal(&yelm)
fmt.Printf ("%s", string(yeml2))

老实说，我在这里有点迷路，谢谢您的帮助

Answer 1

要从您的帖子中获取确切的YAML:

items:
    keys1:value1
    keys2:value2
    keys3:value3
    keys4:value4

您可以这样做(Go Playground):

package main

import (
    "fmt"
    "gopkg.in/yaml.v2"
)

type ItemsStruct struct {
    Items map[string]string `yaml:"items"`
}

func main() {
    itms := &ItemsStruct{Items: map[string]string{
        "keys1": "value1",
        "keys2": "value2",
        "keys3": "value3",
        "keys4": "value4"}}

    yamlBytes, err := yaml.Marshal(itms)
    if err != nil {
        //handle error
    }

    fmt.Println(string(yamlBytes))
}

补充一下，我看到您的代码正在解码此JSON {"key1":"value1", "key2":"value2", ... }，然后以您指定的格式将其编码为YAML。这是Go Playground。