我有模型 View 矩阵、项目 View 矩阵和位置槽以及方形顶点。我想获取 iPhone 屏幕中正方形的屏幕坐标(X、Y 点)。
static GLfloat rectVerts[] = {-0.1f, -0.1f, 0.0f,-0.1f,
0.1f, 0.0f,0.1f, 0.1f,
0.0f,0.1f, -0.1f, 0.0f
,0.0f,0.0f,0.0f,1.0f};
GLKVector4 position_Vector = GLKVector4MakeWithArray(rectVerts);
float p_clip[4];
for (int i=0;i<4;i++){
p_clip[i]=0;
}
for (int i=0;i<4;i++){
for (int j=0;j<12;j++){
p_clip[i] += ( modelViewprojection.m[i + j] * position_Vector.v[j]);
}
}
float p_ndc[4];
p_ndc[0] = p_clip[0] / p_clip[3];
p_ndc[1] = p_clip[1] / p_clip[3];
p_ndc[2] = p_clip[2] / p_clip[3];
p_ndc[3] = p_clip[3] / p_clip[3];
GLint view[4]={0};
glGetIntegerv(GL_VIEWPORT,view);
CGRect rect = CGRectMake(view[0], view[1], view[2], view[3]);
float x = (rect.origin.x + rect.size.width) * (p_ndc[0] + 1) /2;
NSLog(@"Test x = %f",x);
引用附件
最佳答案
只需遵循转换步骤:
p_clip = P · MV · p
p_ndc = p_clip/p_clip.w
p_viewport.xy = viewport.xy + viewport.wh · (p_ndc.xy + 1) / 2
关于iOS:如何从 opengl 模型 View 和投影矩阵获取屏幕坐标(X，Y 点)？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/43318811/